The first step to solving this is converting these mixed numbers into improper fractions. You would do that by multiplying the denominator by the whole number and adding the numerator to that number; this number replaces the numerator. It would look something like this:
1 8/10 --> 18/10
2 2/5 --> 12/5
Now, to subtract the second fraction from the first one, the denominators of both fractions must be the same. We can make them the same by multiplying the second fraction by 2:
12/5 * 2/2 = 24/10
Now we can set up the equation as:
18/10 - 24/10 = -6/10 --> -3/5
The answer is negative 3/5.
I hope this helps.
So,
Since you can only take two one-credit courses every six months, you can earn 2 credits every six months, and 4 credits in one year. Multiplying that by 3, you get 12 credits in 3 years.
It will take 3 years to get the degree.
Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as <span>y=(3/4)X+5
Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:
4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)
Let 's now solve the system
4y=3x + 20
4x-3y=-1
We are to solve this system using subtraction. To accomplish this, multiply the first equation by 3 and the second equation by 4. Here's what happens:
12y = 9x + 60 (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)
Then we have
12y = 9x + 60
-12y =-16x - 4
If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x: 7x = 56; x=8
We were given equations
</span><span>y=3/4X+5
4x-3y=-1
We can subst. x=8 into either of these eqn's to find y. Let's try the first one:
y = (3/4)(8)+5 = 6+5=11
Then x=8 and y=11.
You should check this result. Subst. x=8 and y=11 into the second given equation. Is this equation now true?</span>
The answers are going to be: D & E
Explanation:
Any number that was multiplied by less then one is going to be your answer. :)
You have to rotate it around (0,1) by 90 degrees
