There are infinitely many ways to do this. One such way is to draw a very thin stretched out rectangle (say one that is very tall) and a square. Example: the rectangle is 100 by 2, while the square is 4 by 4.
Both the rectangle and the square have the same corresponding angle measures. All angles are 90 degrees.
However, the figures are not similar. You cannot scale the rectangle to have it line up with the square. The proportions of the sides do not lead to the same ratio
100/4 = 25
2/4 = 0.5
so 100/4 = 2/4 is not a true equation. This numerically proves the figures are not similar.
side note: if you are working with triangles, then all you need are two pairs of congruent corresponding angles. If you have more than three sides for the polygon, then you'll need to confirm the sides are in proportion along with the angles being congruent as well.
Given that the number is x, 10% increase will give us a new number of: 110/100*x =1.1x 10% decrease will give us a new number of: 90/100*1.1x =0.99x This implies the new number is less than the original number
to find the mean, we must add al the numbers and divide it by n
that is,
164,175,178,166,167,145,176,150,174,162,180,156,173,158,182,184,160,172,186,168,195,169,171,187,170 we have to add al these numbers and divide it by 25
Assuming the dotted line at the top is parallel to the segment with length x, it follows from the alternate interior angles theorem that the interior angle of the triangle (marked in diagram) is also 27º.
Using SOH-CAH-TOA, we get that tan(27º) = 21/x, so x = 21/tan(27º), which is approximately equal to 41.2.