<h3>
Answer: y^4 - 2y^3 + 7y^2 + y - 5</h3>
Work Shown:
h(y) = f(y) + g(y)
h(y) = (y^4 - 3y^3 + y - 3) + (y^3 + 7y^2 - 2)
h(y) = y^4 - 3y^3 + y - 3 + y^3 + 7y^2 - 2
h(y) = y^4 + (-3y^3+y^3) + 7y^2 + y + (-3 - 2)
h(y) = y^4 - 2y^3 + 7y^2 + y - 5
This is a fourth degree polynomial (aka quartic).
52 - 38 is 14
since on the second they sold one more child ticket then the first day we know the extra money is the price of a child ticket
so 14 is how much a child ticket is
if 3 senior citizen tickets but 14$ = 38
subtract 14 from38 = 24
and then 24/3 =senior ticket
child:14$
senior:8$
Answer: multiply both sides by 3
Step-by-step explanation: That means it would be (3*x)+(3*2)
T(n) = 5 - 2n
t(2) = 5 - 2(2)
t(2) = 5 - 4 = 1
<span>Answer would be 1</span>
For red peppers lets say R, and for green, let's say G.
So R+G=7
Since he has 3 MORE red peppers than green peppers, R would become (G+3)
Lets rewrite the equation.
G+3+G=7, 2G+3=7 , 2G=4, G=2
Since Nate hase 2 green pepper, he would have 3+2 red peppers.
Nate has 5 Red Peppers
