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zubka84 [21]
3 years ago
7

At the end of the year the production manager is taking inventory and finds 600 units of an older model of invisible fencing tha

t the company no longer manufactures. These obsolete units can be disposed of through their regular channels, thereby incurring variable marketing expenses. What is the lowest price that they should accept for these obsolete units, realizing that if they do not sell them these units will have to be thrown away. (Show all supporting calculations).

Business
1 answer:
KatRina [158]3 years ago
7 0

Answer: $12

Explanation:

In selling the obsolete goods, the company will incur Variable Marketing costs and the alternative will be to throw the goods away.

The relevant costs they will incur are therefore the Variable Marketing costs alone.

The lowest amount that a company should accept for a good is the price that equals it's cost so that they may at least Break-Even.

Seeing as the Variable Marketing Costs are the only relevant cost then the lowest they should accept is the Variable Marketing Costs of $12.

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Which of the following accounts would not be included in the Acquisition and Payment for Long-Lived Assets Cycle? a. Revenue. b.
velikii [3]

Answer:

The correct answer is A

Explanation:

Acquisition and Payment Cycle, also called as the PPP cycle for which the payments, purchases and payables, is mainly comprise of the two classes of the transaction. This cycle is regarding the payables and to pay off the payables with cash.

Acquisition and payment of the long lived assets, which are those assets, the business retain for at least one year. The revenue will not be included in the cycle because it is related to the payables.

7 0
3 years ago
The Rodriquez family is determined to purchase a $250,000 home without incurring any debt. The family plans to save $2,500 a qua
dexar [7]

Answer:

70years

Explanation:

The future value formula for compound interest, after n interest period is

F=P(1+i)^n

where i is the interest rate per period in decimal form and P is the principal or present value.

The Rodriquez family is determined to purchase a $250,000 home so

F=$ 250,000

The family plans to save $2,500 a quarter for this purpose and expects to earn 6.65 percent.

This implies that:

i =  \frac{0.0665}{4}  = 0.0016625

For t years, the number of compounding periods will be;

n = 4t

We fixed the values into the formula and solve for t.

250000=2500(1+0.0066125)^ {4t}

\frac{250000}{2500} =(1.0066125)^ {4t}

100=(1.0066125)^ {4t}

100=(1.0682)^ {t}

t =  log_{1.0682}(100)

t = 69.8

It will take approximately 70years

3 0
3 years ago
OSHA can help a business avoid this type of risk
aniked [119]
What are the risk options ?
3 0
3 years ago
Read 2 more answers
Keynesian economics argues for the use of _____ policy to stabilize the economy.
slavikrds [6]

Answer:

Keynesian economics argues for the use of active government policy to stabilize the economy.

Explanation:

In order to alleviate or avert economic recessions, Keynesian economics places a strong emphasis on the employment of proactive government policy to control aggregate demand. Keynes contended that lengthy periods of high unemployment might result from a lack of general demand. Consumption, investment, government purchases, and net exports are the aggregate of four factors that determine an economy's amount of goods and services.

8 0
2 years ago
You are interested in valuing a 2-year semi-annual corporate coupon bond using spot rates but there are no liquid strips availab
Scorpion4ik [409]

Answer:

Following are the solution to this question:

Explanation:

Assume that r_1  will be a 12-month for the spot rate:

\to 1.25 \% \times \frac{100}{2} \times 0.99 + \frac{(1.25\% \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{100} \times \frac{100}{2} \times 0.99 + \frac{(\frac{1.25}{100} \times \frac{100}{2}+100)}{(1+\frac{r_1}{2})^2}=98\\\\\to \frac{1.25}{2} \times 0.99 + \frac{(\frac{1.25}{2} +100)}{(1+\frac{r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 0.625 +100)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{( 100.625)}{(\frac{2+r_1}{2})^2}=98\\\\\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\

\to 0.61875 + \frac{402.5}{(2+r_1)^2}=98\\\\\to 0.61875 -98 = \frac{402.5}{(2+r_1)^2}\\\\\to -97.38125= \frac{402.5}{(2+r_1)^2}\\\\\to (2+r_1)^2= \frac{402.5}{ -97.38125}\\\\\to (2+r_1)^2= -4.13\\\\ \to r_1=3.304\%

Assume that r_2  will be a 18-month for the spot rate:

\to 1.5\% \times \frac{100}{2} \times 0.99+1.5\%  \times \frac{100}{2} \times \frac{1}{(1+ \frac{3.300\%}{2})^2}+\frac{(1.5\%  \times  \frac{100}{2}+100)}{(1+\frac{r_2}{2})^3}=97\\\\\to \frac{1.5}{100} \times \frac{100}{2} \times 0.99+\frac{1.5}{100}  \times \frac{100}{2} \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{100}  \times  \frac{100}{2}+100)}{(1+\frac{r_2}{2})^3}=97\\\\

\to \frac{1.5}{2}  \times 0.99+\frac{1.5}{2}\times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(\frac{1.5}{2} +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 0.7425+0.75 \times \frac{1}{(1+ \frac{\frac{3.300}{100}}{2})^2}+\frac{(0.75  +100)}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1+0.0165)^2}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4925 \times \frac{1}{(1.033)}+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\

\to 1.4925 \times 0.96+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328+\frac{(100.75 )}{(1+\frac{r_2}{2})^3}=97\\\\\to 1.4328-97= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to -95.5672= \frac{(100.75 )}{(1+\frac{r_2}{2})^3}\\\\\to (1+\frac{r_2}{2})^3= -1.054\\\\\to r_2=3.577\%

Assume that r_3  will be a 18-month for the spot rate:

\to 1.25\% \times \frac{100}{2} \times 0.99+1.25\% \times \frac{100}{2} \times \frac{1}{(1+\frac{3.300\%}{2})^2}+1.25\%\times\frac{100}{2} \times \frac{1}{(1+\frac{3.577\%}{2})^3}+(1.25\% \times \frac{\frac{100}{2}+100}{(1+\frac{r_3}{2})^4})=96\\\\

to solve this we get r_3=3.335\%

4 0
3 years ago
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