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larisa86 [58]
4 years ago
5

"What is the probability that the next two employees that join the office staff will take the bus"

Mathematics
1 answer:
castortr0y [4]4 years ago
7 0

Answer:

The correct option is A.

Step-by-step explanation:

Consider the complete question is "The table shows the transportation method used by the employees in an office.

Transportation   Number  of employees

      Car                      18

      Bus                       6

     Walk                      6

what is the probability that the next two employees that join the office staff will take the bus? A.0.04, B.0.12, C.0.33, D.0.36.

Total number of employees = 18 + 6 + 6 = 30

The probability that the employees take the bus = \frac{6}{30}=0.2

The probability that the employees that join the office staff will take the bus is

Probability=(0.2)\times (0.2)=0.04

Therefore, the correct option is A.

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Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 7%. If the rate of deca
wolverine [178]

Answer:

The amount remaining after 24 hours is 17.5 milligrams.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at a time

The equation is

Rate=k*amount remaining at(time)

Where k = constant of proportionality.

So we don't know the value of k, let's find it.

7= k(70)(6)

K= 1/60

Amount remaining after 24 hours

7= 1/60 * x* (24)

(60*7)/24= x

17.5 = x

The amount remaining after 24 hours is 17.5 milligrams.

3 0
3 years ago
A bank in the Bay area is considering a training program for its staff. The probability that a new training program will increas
WITCHER [35]

Answer:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

See explanation below.

Step-by-step explanation:

For this case we define first some notation:

A= A new training program will increase customer satisfaction ratings

B= The training program can be kept within the original budget allocation

And for these two events we have defined the following probabilities

P(A) = 0.8, P(B) = 0.2

We are assuming that the two events are independent so then we have the following propert:

P(A \cap B ) = P(A) * P(B)

And we want to find the probability that the cost of the training program is not kept within budget or the training program will not increase the customer ratings so then if we use symbols we want to find:

P(B' \cup A')

And using the De Morgan laws we know that:

(A \cap B)' = A' \cup B'

So then we can write the probability like this:

P(B' \cup A') = P((A \cap B)')

And using the complement rule we can do this:

P(B' \cup A') = P((A \cap B)')= 1-P(A \cap B)

Since A and B are independent we have:

P(A \cap B )=P(A)*P(B) =(0.8*0.4) =0.32

And then our final answer would be:

P(B' \cup A') = P((A \cap B)') = 1-P(A \cap B)= 1-0.32=0.68

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