Question

A number is equal to twice a smaller number plus 3. The same number is equal to twice the sum of the smaller number and 1. How many solutions are possible for this situation?

Answer 1

We have the 2 equations:-

N  = 2n + 3

N = 2(n + 1)  or

N = 2n + 2


N cannot be equal to  2n + 3 AND 2n + 2.

Therefore there are no solutions.

Answer 2

There are no solutions for this situation. =)