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Rashid [163]
3 years ago
11

Helppppppp meeeee please

Mathematics
2 answers:
IrinaVladis [17]3 years ago
7 0
6+g-1=4g+7
what is the value of 10-24g
Step 1: solve for g
g+5=4g+7
-2=3g
g=-2/3
Step 2: find 10-24g
24g=24(-2/3)
24g=-16
10-(-16)=26
EastWind [94]3 years ago
7 0

Answer:

<h2>The answer is option D</h2>

Step-by-step explanation:

To find 10 - 24g we must first find g in the expression above

That's

6 + g - 1 = 4g + 7

We have

5 + g = 4g + 7

<u>Subtract g from both sides</u>

That's

5 + g - g = 4g - g + 7

5 = 3g + 7

<u>Subtract 7 from both sides</u>

We have

3g + 7 - 7 = 5 - 7

3g = - 2

Divide both sides by 3

We have the answer as

g =  -  \frac{2}{3}

Now substitute this value into 10 - 24g

That's

10 - 24( -  \frac{2}{3} ) \\ 10 + 16

We have the final answer as

<h2>26</h2>

Hope this helps you

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Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
Question 5
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Step-by-step explanation:

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3 years ago
Simplify the expression
kow [346]

Answer:

<h3>           f(x) = 5x² + 2x</h3><h3>           g(x) = 6x - 6</h3>

Step-by-step explanation:

\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}\\\\6(x^2-3x+2)\ne0\ \iff\ x=\frac{3\pm\sqrt{9-8}}{2}\ne0\ \iff\ x\ne2\ \wedge\ x\ne1\\\\\\\dfrac{5x^3-8x^2-4x}{6x^2-18x+12}=\dfrac{x(5x^2-8x-4)}{6(x^2-3x+2)}=\dfrac{x(5x^2-10x+2x-4)}{6(x^2-2x-x+2)}=\\\\\\=\dfrac{x[5x(x-2)+2(x-2)]}{6[x(x-2)-(x-2)]} =\dfrac{x(x-2)(5x+2)}{6(x-2)(x-1)}=\dfrac{x(5x+2)}{6(x-1)}=\dfrac{5x^2+2x}{6x-6}\\\\\\f(x)=5x^2+2x\\\\g(x)=6x-6

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3 years ago
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