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Bond [772]
2 years ago
5

Help on this please.

Mathematics
1 answer:
Komok [63]2 years ago
6 0

Answer:

80 or 81

Step-by-step explanation:

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I need help with this asap!!!! ​
Yuri [45]

Answer:

26.6 but that is not one of yor answers...

I think you have a typo in "A"

I think that your have a typo in the answers

x/sin(40) = 32/sin(90)

x = 26.6

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Please help me!! I really need it!! I Could fail the 7th grade
babymother [125]

Answer:

Step-by-step explanation:

Price of one ticket   = $4

Price of t tickets = 4t

1) 4t + 72 > 400

   t >  (400-72)/4

2) 4t + 72 > 400      

4t + 72 - 72 > 400 - 72    {subtract 72 from both sides}

4t > 328

4t/4 > 328/4      {divide both sides  by 4}

t >  82

7 0
3 years ago
What is the product of (9)(-9)(-1)?
LekaFEV [45]
The product of this is 81
5 0
3 years ago
britney is buying a hat at the mall. the shirt costs $31.59, and the hat costs $19.46. if Britney gives the sales clerk $100.00,
kiruha [24]

Answer: 48.95

Step-by-step explanation:

so first I would add together the cost of the shirt and hat

31.59 +19.46 = 51. 05

then I would take away the 51.05 ( the total ) from $100

100 - 51.05 = $48.95

So she would get $48.95 for change

7 0
3 years ago
(1 point) A pond contains 100 fish, of which 40 are carp. If 20 fish are caught from the lake, what are the mean and variance of
marta [7]

Answer:

E(X) = 6

Var(X) = 3.394

Step-by-step explanation:

Let X represent the number of carp caught out of the 20 fishes caught. Now, if we are to assume that each

of the (100, 20) ways to catch the 20 fishes will be equally likely.

Thus, we can say that X fulfills a hypergeometric

distribution with parameters as follows;

n = 20, N = 100, k = 30

Formula for expected mean value in hypergeometric distribution is;

E(X) = nk/N

E(X) = (20 × 30)/100

E(X) = 6

Formula for variance is;

Var(X) = (nk/N) × [((n - 1)(k - 1)/(N-1))) + (1 - nk/N)]

Var(X) = ((20 × 30)/100) × [((20 - 1)(30 - 1)/(100 - 1)) + (1 - (20 × 30/100)]

Var(X) = 6 × 0.5657

Var(X) = 3.394

5 0
2 years ago
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