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Hunter-Best [27]
3 years ago
12

Find the x - intercept of the graph of the equation

Mathematics
1 answer:
Alborosie3 years ago
5 0

Answer:

ugh should i drop out

Step-by-step explanation:

You might be interested in
What is 7/9 - 5/18 lowest common denominator
NISA [10]
7/9 = 14/18
14-5=9
9/18=1/2
6 0
3 years ago
Read 2 more answers
a cashier at the supermarket has $685 in 4 different denomination bills in her register at the end of the day. the number of $5
netineya [11]

9514 1404 393

Answer:

  • 85 ones
  • 70 fives
  • 15 tens
  • 2 fifties

Step-by-step explanation:

Let a, b, c, d represent the numbers of $1, $5, $10, and $50 bills, respectively. The problem statement tells us ...

  a +5b +10c +50d = 685 . . . . . total amount of cash

  b = 10 +4c . . . . . . . . . . . . the number of fives is 10 more than 4 times tens

  a = b+c . . . . . . . . . . . as many ones as fives and tens combined

  d = 2 . . . . . . . . . . the register contained 2 fifty-dollar bills

__

Substituting for 'a', then for 'b', we have ...

  (b+c) +5b +10c +50d = 685

  6(10 +4c) +11c +50d = 685

  60 +35c +50d = 685

Substituting d=2 and subtracting 160 gives ...

  35c = 525

  c = 15

  b = 10 +4c = 10 +4(15) = 70

  a = b+c = 70 +15 = 85

The register contained ...

  • 85 ones
  • 70 fives
  • 15 tens
  • 2 fifties
5 0
3 years ago
Read 2 more answers
Me remaining days
Alex73 [517]
Well $25 is the standard price initially.

$10 is added every hour as a constant rate.

Therefore a. 25 + 10h is the right expression
4 0
3 years ago
The table shows the results of an experiment in which subjects taking either a drug or a placebo either reported fatigue or did
Lady bird [3.3K]

Answer:

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Step-by-step explanation:

Here we have that for dependent events,

P(A \, and \, B)= P(A)\times  P(B\left |  \right A )

From the options, we have;

P(fatigue \left |  \right drug) = 0.533

P(drug) = 0.6

P(drug and fatigue) = 0.32

Therefore

P(drug and fatigue) = P(drug)×P(fatigue \left |  \right drug)  

= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)

Therefore, the correct options are;

-P(fatigue) = 0.44

P(fatigue \left |  \right drug) = 0.533

--P(drug and fatigue) = 0.32

P(drug)·P(fatigue) = 0.264

Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.

4 0
3 years ago
Jess observed that 60% of the people at a mall on a particular day shopped for clothes. If 2500 people at the mall did not shop
GalinKa [24]
2500 is 40% of the 100%
so, from the 40%, figure out 10%
2500/4=600
600 x 6=3,600
so, 3,600 is the answer
7 0
3 years ago
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