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4 years ago

5

Analyze the diagram below and complete the instructions that follow.

1 answer:

ElenaW [278]4 years ago

4 0

Answer:

D. 126°

Step-by-step explanation:

The exterior angle is equal to the sum of the opposite interior angles:

(3x)° = x° + 84°

2x = 84 . . . . . divide by °, subtract x

x = 42 . . . . . . divide by 2

(3x)° = 126° . . . . multiply by 3 to find ∠FEG.

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Question 2 (2 points)

hoa [83]

Answer:

4) The limit does not exist.

General Formulas and Concepts:

<u>Calculus</u>

Limits

Right-Side Limit: $\displaystyle \lim_{x \to c^+} f(x)$
Left-Side Limit: $\displaystyle \lim_{x \to c^-} f(x)$

Limit Rule [Variable Direct Substitution]: $\displaystyle \lim_{x \to c} x = c$

Step-by-step explanation:

*Note:

For a limit to exist, the right-side and left-side limits must be equal to each other.

<u>Step 1: Define</u>

<em>Identify</em>

$\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x ,\ x < 5\\8 ,\ x = 5\\x + 3 ,\ x > 5\end{array}$

<u>Step 2: Find Left-Side Limit</u>

Substitute in function [Left-Side Limit]: $\displaystyle \lim_{x \to 5^-} 5 - x$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^-} 5 - x = 5- 5 = 0$

<u>Step 2: Find Left-Side Limit</u>

Substitute in function [Right-Side Limit]: $\displaystyle \lim_{x \to 5^+} x + 3$
Evaluate limit [Limit Rule - Variable Direct Substitution]: $\displaystyle \lim_{x \to 5^+} x + 3 = 5 + 3 = 8$

∴ since $\displaystyle \lim_{x \to c^+} f(x) \neq \lim_{x \to c^-} f(x)$ , $\displaystyle \lim_{x \to 5} f(x) = \text{DNE}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

5 0

3 years ago

5.<br> Solve<br> 3/5x + 1/3 <4/5x+-1/3

mihalych1998 [28]

Answer:

Inequality form: x>10/3

Interval Notation: (10/3, infinity)

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

3 0

3 years ago

Read 2 more answers

A student solves the following equation and determines that the solution is −2. Is the student correct? Explain. 3 a + 2 − 6a a2

Ganezh [65]

For this case, we have the following equation (according to the comments):

$\frac{3}{a+2} - \frac{6a}{a^2-4} = \frac{1}{a-2}$

First, we factor the quadratic expression in the denominator:

$\frac{3}{a+2} - \frac{6a}{(a-2)(a+2)} = \frac{1}{a-2}$

Then, we multiply both sides of the equation by (a-2) (a + 2):

$\frac{3(a-2)(a+2)}{a+2} - \frac{6a(a-2)(a+2)}{(a-2)(a+2)} = \frac{(a-2)(a+2)}{a-2}$

Later, canceling similar terms we have:

$3(a-2) - 6a = a+2$

We do distributive property on the left side of the equation:

$3a-6-6a=a+2$

By grouping variables and constant terms we have:

$3a - 6a -a = 2+6$

Rewriting we have:

$-4a=8$

Finally, by clearing "a" we have:

$a=-\frac{8}{4} a=-2$

Note: the value of a is a extraneous solution because it makes the denominator of the original equation equal to zero.

Answer:

the student correct, but the value of a= -2 is an extraneous solution

8 0

4 years ago

Read 2 more answers

Solve the equation by completing the square. 3x^2 -4x =-2

blsea [12.9K]

This is the answer!!!!!!!

5 0

3 years ago

Read 2 more answers

When two times a number is decreased by 3 the result is 11 what is the number

Paraphin [41]

2x - 3 = 11

Solve:

2x = 14

x = 7

The answer is 7

4 0

3 years ago

Read 2 more answers