When calculating interest accrued, you should ____.

Mathematics

1 answer:

Ber [7]3 years ago

4 0

Answer:

(B)

Step-by-step explanation:

Interest accrued is defined as the interest which we need to pay at the end of some time span. The interest accrued may be on daily basis as well as on monthly basis.

For calculating the interest accrued, we first multiply the principal amount with APR, this will give the interest of one year.

Then we will multiply it with the no. of months on which the interest is being calculated and divide it by total no. of months.

This will give the interest accrued every month.

When calculating interest accrued, you should <u>multiply the principal by the APR and number of months, then divide by the total number of months in the year.</u>

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The average sales per customer at a home improvement store during the past year is $75 with a standard deviation of $12. The pro

borishaifa [10]

Answer:

0.0668

Step-by-step explanation:

Assuming the distribution is normally distributed with a mean of $75,

with a standard deviation of $12.

We can find the z-score of 78 using;

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n} } }$

$\implies z=\frac{78-75}{\frac{12}{36} } =1.5$

Using our normal distribution table, we obtain the area that corresponds to 0.25 to be 0.9332

This is the area corresponding to the probability that, the average is less or equal to 78.

Subtract from 1 to get the complement.

P(x>78)=1-0.9332=0.0668

6 0

3 years ago

Is the answer A, B, or C?

Olegator [25]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Calculate all four second-order partial derivatives and confirm that the mixed partials are equal. f(x,y)= 2e^xy

nadya68 [22]

ANSWER TO QUESTION 1

The given function is

$f(x,y)=2 {e}^{xy}$

The partial derivative of f with respect to x means we are treating y as a constant. The first derivative is

$f_{x} = 2y {e}^{xy}$

and the second derivative with respect to x is,

$f_{xx} = 2 {y}^{2} {e}^{xy}$

ANSWER TO QUESTION 2

The given function is

$f(x,y)=2 {e}^{xy}$

The partial derivative of f with respect to y means we are treating x as a constant. The first derivative is

$f_{y} = 2x{e}^{xy}$

and the second derivative with respect to y is

$f_{yy} = 2 {x}^{2} {e}^{xy}$

ANSWER TO QUESTION 3

Our first mixed partial is

$f_{xy}$

We need to differentiate
$f_{x} = 2y {e}^{xy}$
again. But this time with respect to y.

Since this is a product of two functions of y, we apply the product rule of differentiation to obtain,

$f_{xy} = 2y( {e}^{xy})' + ({e}^{xy})(2y)'$

$f_{xy} = 2xy {e}^{xy} + 2{e}^{xy}$

ANSWER TO QUESTION 4

The second mixed partial is

$f_{yx}$

We need to differentiate
$f_{y} = 2x{e}^{xy}$

again. But this time with respect to x.

Since this is a product of two functions of x, we apply the product rule of differentiation to obtain,

$f_{yx} = 2x({e}^{xy})' + ({e}^{xy})(2x)'$

$f_{yx} = 2xy {e}^{xy} + 2{e}^{xy}$

Hence,

$f_{xy} = 2xy {e}^{xy} + 2{e}^{xy} =f_{yx}$