A members-only speaker series allows people to join for $23 and then pay $1 for every

Mathematics

1 answer:

givi [52]3 years ago

7 0

So it’s 23 followers to join and they charge them $1 an event which is 44 dollars and event

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PLZ HELP REALLY FAST!!

frutty [35]

The answer your looking for is C

7 0

2 years ago

Read 2 more answers

Select the correct answer from each drop-down menu.

ella [17]

Answer:

A non-equilateral rhombus.

Step-by-step explanation:

We can solve this graphically.

We start with square:

ABCD

with:

A = (11, - 7)

B = (9, - 4)

C = (11, - 1)

D = (13, - 4)

Only with the vertices, we can see that ABCD is equilateral, as the length of each side is:

AB = √( (11 - 9)^2 + (-7 -(-4))^2) = √( (2)^2 + (3)^2) = √(4 + 9) = √13

BC = √( (11 - 9)^2 + (-1 -(-4))^2) = √13

CD = √( (11 - 13)^2 + (-1 -(-4))^2) = √13

DA = √( (11 - 13)^2 + (-7 -(-4))^2) = √13

And we change C by C' = (11, 1)

In the image you can see the 5 points and the figure that they make:

The figure ABCD is a rhombus, and ABC'D is also a rhombus, the only difference between the figures is that ABCD is equilateral while ABC'D is not equilateral.

5 0

2 years ago

A scientist has 100 milligrams of a radioactive element. The amount of radioactive element remaining after t days can be determi

grandymaker [24]

The mass of the first shipment at time t is
$m_{1}=100( \frac{1}{2} )^{ \frac{t}{10}}$

The mass of the second shipment at time t is
$m_{2}=100( \frac{1}{2} )^{ \frac{t-3}{10} }$

At time t, the ratio of m₁ to m₂ is
$\frac{m_{1}}{m_{2}} = \frac{100}{100}. \frac{(1/2)^{t/10}}{(1/2)^{(t-3)/10}} \\ = \frac{(1/2)^{t/10}}{(1/2)^{t/10}}. \frac{1}{(1/2)^{-3/10}} \\ = (1/2)^{3/10} \\ = 0.8123$

Therefore as a percentage,
$\frac{m_{1}}{m_{2}} =100*0.8123 = 81.23 \%$

Answer: B. 81.2%

4 0

3 years ago

What is the value of x in the equation x - y = 30, when y = 15?<br> O4<br> O 8<br> O 80<br> O 200

olganol [36]

$\frac{1}{5}x - \frac{2}{3} y = 30 \\$