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3 years ago

At a used book sale, 5 books cost $15. What is the cost per book?

Mathematics

1 answer:

Arte-miy333 [17]3 years ago

4 0

Answer:

$3/book

Step-by-step explanation:

cost per book means divide the price of all the books by the number of books

$15/(5 books) = $3/book

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A circle with a radius of 1 unit

oee [108]

Answer:

C= 6.28 A: 3.14

Step-by-step explanation:

Circumference of a circle is 2* pi * r

Based on this, we can subsitute r for 1

2* pi * 1= 2pi which is around 6.28 units

Area of a circle is pi* r* r

Based on this, we can subsitute r for 1

pi* 1* 1= pi= 3.14 units squared

8 0

3 years ago

Which value, in order, will complete the table?

tia_tia [17]

Answer: The answer is the first choice.

Explanation:

Because you must find the sin of the x values in the table.

Sin(7pi/6) = -1/2

Sin(5pi/4) = -sqrt 2/2

Sin(4pi/3) = -sqrt 3/2

4 0

3 years ago

A movie theater sold 40 juice boxes. The cashier noticed that 75% of the boxes were apple juice.

lozanna [386]

30 of them would be apple juice boxes.

40 x 75% = 30

3 0

3 years ago

The skoblickis are building a new home. The scale drawing below shows their master bedroom. Find the length and width of the act

jolli1 [7]

Answer:

Length: 20

Width:15

Step-by-step explanation:

Hope this Helps!

3 0

2 years ago

Evaluate the integral by making an appropriate change of variables.

VARVARA [1.3K]

By inspecting the integrand, the "obvious" choice for substitution would be

u = y + x

v = y - x

Solving for x and y, we would have

x = (u - v)/2

y = (u + v)/2

in which case the Jacobian and its determinant are

$J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12$

The trapezoid R has two of its edges on the lines x + y = 8 and x + y = 9, so right away, we have 8 ≤ u ≤ 9.

Then for v, we observe that when x = 0 (the lowest edge of R), v = y ; similarly, when y = 0 (the leftmost edge of R), v = -x. So

-x ≤ v ≤ y

-(u - v)/2 ≤ v ≤ (u + v)/2

-u + v ≤ 2v ≤ u + v

-u ≤ v ≤ u

So, the integral becomes

$\displaystyle\iint_R5\cos\left(7\frac{y-x}{y+x}\right)\,\mathrm dA=\int_8^9\int_{-u}^u\frac52\cos\left(\frac{7v}u\right)\,\mathrm dv\,\mathrm du$

$=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du$

$=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du$

$=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}$

4 0

3 years ago