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cestrela7 [59]
3 years ago
15

How to solve 55% of 600 with a visual

Mathematics
1 answer:
Zanzabum3 years ago
4 0
1. We assume, that the number 600 is 100% - because it's the output value of the task. 
<span>2. We assume, that x is the value we are looking for. </span>
<span>3. If 600 is 100%, so we can write it down as 600=100%. </span>
<span>4. We know, that x is 55% of the output value, so we can write it down as x=55%. </span>
5. Now we have two simple equations:
1) 600=100%
2) x=55%
where left sides of both of them have the same units, and both right sides have the same units, so we can do something like that:
600/x=100%/55%
6. Now we just have to solve the simple equation, and we will get the solution we are looking for.

<span>7. Solution for what is 55% of 600</span>
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kondaur [170]

Answer:

a=0.5

Step-by-step explanation:

Divide each term by  8x+ 7  and simplify.

Hope this helps :)

<em>-ilovejiminssi♡</em>

6 0
3 years ago
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A plane flying horizontally at an altitude of 3 miles and a speed of 500 mi/h passes directly over a radar station. Find the rat
konstantin123 [22]

Answer:

The rate at which the distance from the plane to the station is increasing is 331 miles per hour.

Step-by-step explanation:

We can find the rate at which the distance from the plane to the station is increasing by imaging the formation of a right triangle with the following dimensions:

a: is one side of the triangle = altitude of the plane = 3 miles

b: is the other side of the triangle = the distance traveled by the plane when it is 4 miles away from the station and an altitude of 3 miles

h: is the hypotenuse of the triangle = distance between the plane and the station = 4 miles                    

First, we need to find b:    

a^{2} + b^{2} = h^{2}   (1)    

b = \sqrt{h^{2} - a^{2}} = \sqrt{(4 mi)^{2} - (3 mi)^{2}} = \sqrt{7} miles

Now, to find the rate we need to find the derivative of equation (1) with respect to time:

\frac{d}{dt}(a^{2}) + \frac{d}{dt}(b^{2}) = \frac{d}{dt}(h^{2})

2a\frac{da}{dt} + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

Since "da/dt" is constant (the altitude of the plane does not change with time), we have:  

0 + 2b\frac{db}{dt} = 2h\frac{dh}{dt}

And knowing that the plane is moving at a speed of 500 mi/h (db/dt):

\sqrt{7} mi*500 mi/h = 4 mi*\frac{dh}{dt}

\frac{dh}{dt} = \frac{\sqrt{7} mi*500 mi/h}{4 mi} = 331 mi/h  

Therefore, the rate at which the distance from the plane to the station is increasing is 331 miles per hour.

I hope it helps you!

4 0
3 years ago
HELP ASAP
IrinaVladis [17]

Answer:

y-5=(x-6)?

Step-by-step explanation:

Hope this helped!

-BB

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3 years ago
The price of a visit to the dentist is $50 . If the dentist fills any cavities, an additional charge of, 100$ per cavity gets ad
frozen [14]
The cost of the visit to the dentist can be expressed as the cost equals 100x+50.

The initial cost of the appointment would be $50; no matter how many cavities one has, they would still have to pay $50.

The cost of each cavity is represented as 100x, because each cavity costs $100. x represents the number of cavities, as we do not know how many cavities there are.
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Someone please explain the answer to me
tia_tia [17]
You can divide the fractions
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4 years ago
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