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3 years ago

7

Whats the surface area of the prism below,and please explain how you got the answer :)

1 answer:

nevsk [136]3 years ago

4 0

Answer: 480 units^2

IN DEPTH EXPLANATION TO HELP YOU FOR FUTURE PROBLEMS:

Front:
b*h/2 = sa
12*5/2 = 30
Front = 30 units^2

Back:
b*h/2 = sa
12*5/2 = 30
Back = 30 units^2

Right:
w*l = sa
14*13 = 182 units^2
Right: 182 units*2
(figures out the length by using
pythagorean theorem)

Left:
w*l = sa
5*14 = 70 units^2
Left: 70 units^2

Bottom:
w*l = sa
12*14 = 168 units^2

ADD ALL THE UNITS:
168 + 70 + 182 + 30 + 30 = 480

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If a vertical line is dropped from the x-axis to the point (12, –9) in the diagram below, what is the value of sec?

dem82 [27]

Answer:

Value of $\sec \theta = \frac{5}{4}$

Step-by-step explanation:

Given: A vertical line is dropped from the x-axis to the point (12, -9) as shown in the diagram below;

To find the value of $\sec \theta$ .

By definition of secants;

$\sec \theta = \frac{1}{\cos \theta}$

Now, first find the cosine of angle $\theta$

As the point (12 , -9) lies in the IV quadrant , where $\cos \theta > 0$

Consider a right angle triangle;

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Using Pythagoras theorem;

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or

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