By definition we have that the average rate of change is given by:
AVR = (f (x2) - f (x1)) / (x2 - x1)
Substituting the values we have:
AVR = (204 - (-6)) / (10 - 0)
Rewriting we have:
AVR = (204 + 6) / (10 - 0)
AVR = 210/10
AVR = 21
Answer:
the average rate of change for f (x) from x = 0 to x = 10 is:
AVR = 21
Answer:
cylinder has greatest volume
Step-by-step explanation:
solution
given,
radius of cylinder(r)=6cm
height of cylinder (h)=6cm
we know,
volume of cylinder=πr^2h
=22÷7×6×6×6
=4752÷7
=678.857cm^3
radius of cone(r)=6cm
height of cone(h)=12cm
we know,
volume of cone=1÷3πr^3
= 1÷3×22÷7×6×6×6
= 4752÷21
=226.2857cm^3
as a result,cylinder has greatest volume
Let h = height of the box,
x = side length of the base.
Volume of the box is

.
So

Surface area of a box is S = 2(Width • Length + Length • Height + Height • Width).
So surface area of the box is


The surface are is supposed to be the minimum. So we'll need to find the first derivative of the surface area function and set it to zero.

![4x = \frac{460}{ x^{2} } \\ 4x^{3} = 460 \\ x^{3} = 115 \\ x = \sqrt[3]{115} = 4.86](https://tex.z-dn.net/?f=%204x%20%3D%20%5Cfrac%7B460%7D%7B%20x%5E%7B2%7D%20%7D%20%20%5C%5C%20%204x%5E%7B3%7D%20%3D%20460%20%20%5C%5C%20x%5E%7B3%7D%20%3D%20115%20%20%5C%5C%20x%20%3D%20%20%5Csqrt%5B3%5D%7B115%7D%20%3D%204.86%20)
Then

So the box is 4.86 in. wide and 4.87 in. high.
Answer:
To find the answer to these questions, you normaly divide the distance by the time, and then you know how long it took and multiply it by the new distance.
Step-by-step explanation:
110/10=11
to jog one mile it took her 11 minutes
Answer:
a) In 5 weeks he would have $50
b)w | m
1 : $10
2: $20
3:$30
Step-by-step explanation: