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Svetlanka [38]
3 years ago
12

The rectangle below has a length of 4x+3 and a width of 3x.

Mathematics
1 answer:
Irina18 [472]3 years ago
4 0
Perimeter- 14x+6
Just add al the sides up like normal
Area- 12x^2+9x
Multiply the length and width
C)
Perimeter- 118
Area- 840

I’m pretty sure these are right

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Evaluate ƒ(x) when x = 6. <br><br> A. 6 (NOT the answer)<br> B. 12 <br> C. 74 <br> D. 218
Andrej [43]
After trying to do it the hard way, i remembered the easy way.

substitution:

because x = 6 and 6 is in the range of -6 < x < 9, we only need the equation 6x^(2) + 2

f(x) = 6x^(2) + 2
f(6) = 6(6)^(2) + 2
f(6) = 6(36) + 2
f(6) = 216 + 2
f(6) = 218
6 0
3 years ago
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Margarita [4]

Answer:

100% of 188=188

50% of 188=94

25% of 188=47

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Step-by-step explanation:

3 0
2 years ago
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I need a little bit of help here ☹️
Grace [21]
-3(y+2)^2 - 5 + 6y
= -3(y^2 + 4y + 4) - 5 + 6y
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Answer
(-1) y^2 + (-6) y + (-17)
3 0
3 years ago
Suppose f(x) = x^2– 7. and g(x) = 5 – x^2 ,then g(f(-4)) =
iogann1982 [59]

Answer:

-76

Step-by-step explanation:

f(x) = x^2– 7. and g(x) = 5 – x^2 ,then g(f(-4)) =

-76

7 0
3 years ago
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A set of numbers is shown below: {0, 0.6, 2, 4, 6} Which of the following shows all the numbers from the set that make the inequ
Lorico [155]
The given equality hold true when x = 2.

Put x = 2 in inequality.

2(2) + 3 = 4+3 = 7 = R.H.S.

For x = 4 and 6, L.H.S(2x+3) is greater than 7.

Hence for x = 2, 4 and 6, the above inequality holds true.

Hope this helps!
3 0
3 years ago
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