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antoniya [11.8K]

3 years ago

14

In a certain test, the number of successful candidates was three times than that of unsuccessful candidate, if there had been 16

fewer candidates and if 6 more would have been unsuccessful, the number would have been as 2 to 1. Find the number of candidates.

1 answer:

Natali5045456 [20]3 years ago

3 0

Answer:

The number of candidates is 136.

Step-by-step explanation:

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What does an exponent represent, given 7^3? Simplify

MrRa [10]

Answer:

7³= 343

Step-by-step explanation:

it indicates that the base is to be raised to a certain power

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Rus_ich [418]

Answer:

93.5

Step-by-step explanation:

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3 years ago

Someone please help, I really don't understand!!

nika2105 [10]

?.....OH these are steps xD

a. and b.
<span>P(1,2,0), Y(-2,3,0), R(3,4,0), and A (2,1,5).

c. and d.</span><span>
</span>P(3,6,-3), Y(0,7,-3), R(5,8,-3), and A (4,5,2).

8 0

3 years ago

In 2000, Canada produced 3.0 million new motor vehicles. In 2006, it produced 2.5 million. Write the linear equation (in slope-i

kogti [31]

To begin, you are given two point that this function would intercept: (0,3) where the 0 is the original year (2000) and 3 is the amount of million cars sold. The next point would be (6,2.5) Where the 6 is the 6 years later and the 2.5 is the 2.5 million cars sold. Since we have 2 points, we can work out the gradient by finding the rate of change in y and dividing by the rate of change in x:
$\frac{y_{1}- y_{2} }{x_{1}- x_{2} }$

We then substitute in the points:
$x_{1} =3$
$y_{1} =0$
$x_{2} =2.5$
$y_{2} =6$

$\frac{3-2.5}{0-6}$
$=\frac{0.5}{-6}$
$=-.083$

Because we started on the y-intercept of (0,3), we already have our intercept value of 3. If we did not start with the y-intercept given, we could substitute in a point to solve for it:

Using point (2.5,6):

<span> $2.5=-0.083*6+c$
</span> $2.5=-0.5+c$
$2.5+0.5=c$
$c=3$

Hope this helps :)

5 0

3 years ago

Suppose a 90% confidence interval for the mean salary of college graduates in a town in Mississippi is given by [$38,737, $50,46

JulsSmile [24]

Answer:

a. The point estimate was of $44,600.

b. The sample size was of 16.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

A confidence interval is symmetric, which means that the point estimate used is the mid point between these two bounds, that is, the mean of the two bounds.

The margin of error is the difference between the two bounds, divided by 2.

a. What is the point estimate of the mean salary for all college graduates in this town?

Mean of the bounds, so:

(38737+50463)/2 = 44600.

The point estimate was of $44,600.

b. Determine the sample size used for the analysis.

First we need to find the margin of error, so:

$M = \frac{50463-38737}{2} = 5863$

Relating the margin of error with the sample size:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.9}{2} = 0.05$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.05 = 0.95$ , so Z = 1.64.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

For this problem, we have that $\sigma = 14300, M = 5863$ . So

$M = z\frac{\sigma}{\sqrt{n}}$

$5863 = 1.645\frac{14300}{\sqrt{n}}$

$5863\sqrt{n} = 1.645*14300$

$\sqrt{n} = \frac{1.645*14300}{5863}$

$(\sqrt{n})^2 = (\frac{1.645*14300}{5863})^2$

$n = 16$

The sample size was of 16.

7 0

3 years ago