The answer should be I think b
Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

Answer:
10 kiloliter to liters, the result is 10000 liters
if i helped then please give brainliest and a thanks!
4 times 18 is 72 use a calculator and divide 72 by each number and you’ll find numbers
N= 15
M= 15 √ 3
Brainliest please