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zubka84 [21]
3 years ago
8

Write the equation of a line that passes through the points (−3, 7) and (3, 3)

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
3 0

Step-by-step explanation:

You can write an equation of a line conveniently by point-slope form. It's in the form of y -a = m(x -b) where (b,a) is the coordinates of a point that's on the line and m is the slope of the line.

Now choose a point (It doesn't really matter which one) and plug that in the equation. I'll choose (-3,7) where a = 7 and b = -3

y -a = m(x -b) \\ y -7 = m(x -(-3)) \\ y -7 = m(x +3)

The next thing we have to do now is finding the slope, m, where it's equal to \frac{y_{2} -y_{1}}{x_{2} -x_{1}}\\. I'll make (-3,7) point 1 and (3,3) point 2.

m = \frac{3 - 7}{3 -(-3)} \\ m = \frac{3 - 7}{3 +3} \\ m = \frac{-4}{6} \\ m = -\frac{2}{3}

Now let's plug that to our equation.

y -7 = m(x +3) \\ y -7 = -\frac{2}{3}(x +3)

Now we have the equation but out of all the choices it seemed that all of them are in slope-intercept form all you have to do now is make our equation rewrite it in slope-intercept form.

y -7 = -\frac{2}{3}(x +3)\\ y -7 = -\frac{2}{3}x -\frac{2}{3}(3) \\ y - 7 = -\frac{2}{3}x -2\\ y = -\frac{2}{3}x +5

<h3>Answer:</h3>

y = -\frac{2}{3}x +5\\ is your equation.

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