All categories

2 years ago

Find the total price, including 5 percent tax, for a 7.95 dinner a .90 beverage and a 2.35 dessert.

1 answer:

7 0

To find percent tax, add the cost of the meal, which would be 11.20. A 5% tax would be 11.20*0.05=$0.56. This would be added on to the bill. So 11.20+0.56. This means the total cost of the meal is $11.76

You might be interested in

The Wares want to buy a new computer. The regular price is $1,049. The store is offering a 20% discount and a sales tax of 4.25%

MariettaO [177]

Answer:

so if you offer 20% off of 1,049 you get 209.8. If the tax is 4.25% then do the math -._-. (thinking)... 200.8835 and just do the lil bit of math to find your answer.

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Fill in the blanks for this geometry problem. Translation, reflection, etc type of problem. 70 POINTS!

Shkiper50 [21]

The answer is translation of 2 units left and a reflection over the x-axis.

The triangle is translated 2 units left because the triangle moved two units to the left and it is reflected over the x-axis because the bottom triangle is like a reflection of the original triangle.

7 0

2 years ago

Can someone help me?<br> (A) 1.5<br> (B) 3<br> (C) 4.5<br> (D) 6

zhenek [66]

Find the horizontal distance of 230 and find the Vertical distance , which is where the black dot is located.

The black dot is on 49 inches.

Now find the vertical distance f the black line at horizontal 230: This is on 47.5.

The difference between the two is : 49 - 47.5 = 1.5

The answer would be A. 1.5

6 0

2 years ago

Read 2 more answers

Consider The following pair of equations the two equations are graft at what point do the lines representing the two equations i

ANEK [815]

Answer:

Step-by-step explanation:

hope this helps please brainiest

4 0

2 years ago

A 140 kg camera is suspended by two wires over a 40 metre wide football field to get shots of the action from above. At one poin

Katen [24]

Answer:

Please red the answer below

Step-by-step explanation:

In order to determine the length of each cable you use the Newton second law for each component of the forces involved in the situation.

For the x component you have:

$T_1cos\theta_1-T_2cos\theta_2=0$ (1)

T1: tension of the first cable = 1500N

T2: tension of the second cable = 800N

θ1: angle between the horizontal and the first cable

θ2: angle between the horizontal and the first cable

For the y component you have:

$T_1sin\theta_1+T_2sin\theta_2-W=0$ (2)

W: weight of the camera = Mg = (140kg)(9.8m/s^2) = 1372N

You can squared both equations (1) and (2) and the sum the two equations:

$T_1^2cos^2\theta_1=T_2^2cos^2\theta_2\\\\T_1^2sin^2\theta_1=T_2^2sin^2\theta_2-2WT_2sin\theta_2+W^2$

Then, you sum the equations:

$T_1^2(cos^2\theta_1+sin^2\theta_1)=T_2^2(sin^2\theta_2+cos^2\theta_2)-2Wsin\theta_2+W^2$ (3)

Next, you use the following identity:

$sin^2\theta+cos^2\theta=1$

and you obtain in the equation (3):

$T_1^2=T_2^2-2WT_2sin\theta_2+W^2\\\\sin\theta_2=\frac{T_2^2-T_1^2+W^2}{2WT_2}=\frac{(800N)^2-(1500)^2+(1372N)^2}{2(800N)(1372N)}=0.066\\\\\theta_2=sin^{-1}0.066=27.23\°$

With this values you can calculate the value of the another angle, by using the equation (1):

$\theta_1=cos^{-1}(\frac{T_2cos(27.23\°)}{T_1})=cos^{-1}(\frac{(800N)(cos27.23\°)}{1500N})\\\\\theta_1=61.69\°$

Now, you can calculate the length of each cable by using the information about the width of the football field. You use the following trigonometric relation:

$l_1cos\theta_1=40-d\\\\l_2cos\theta_2=d\\\\$

d: distance to the right side of the field

By using the cosine law you can fins a system of equation and then you can calculate the values of l1 and l2.

3 0

2 years ago