A restaurant that can hold 300 people is divided into 20 equal parts. How many people can be put in each section?

An office will randomly select one computer to check for viruses and other problems. Five of the office computers are less than

alisha [4.7K]

Your answer is going to be 4/9 :)

3 0

4 years ago

Read 2 more answers

Heme d hey the girl who helped me please hl

mestny [16]

Answer:

Parallel segments → 1

perpendicular segments → 2

congruent segments → 3

$---------$

hope it helps...

have a great day!!

5 0

3 years ago

Read 2 more answers

Solve the system of equations using substitution and Elimination

juin [17]

<h2>Greetings!</h2>

Answer:

y = $\frac{-18}{7}$ and x = $\frac{50}{7}$

Step-by-step explanation:

To solve simultaneous equations, you need to have the number in front of both x's or y's the same. (signs doesn't matter)

To get -x to -10x we simply need to multiply the first equation by 10:

-x * 10 = -10x

-9y * 10 = -90y

16 * 10 = 160

-10x - 90y = 160

Now we can add the two equations:

-10x + 10x = 0

-90y + 20y = -70y

160 + 20 = 180

-70y = 180

70y = -180

7y = -18

y = $\frac{-18}{7}$

Now plug $\frac{-18}{7}$ into the second equation:

10x + 20( $\frac{-18}{7}$ ) = 20

10x - $\frac{360}{7}$ = 20

Move the $\frac{360}{7}$ over to the other side, making it a positive:

10x = 20 + $\frac{360}{7}$

10x = $\frac{500}{7}$

Divide both sides by 10:

x = $\frac{50}{7}$

So y = $\frac{-18}{7}$ and x = $\frac{50}{7}$

<h2>Hope this helps!</h2>

5 0

3 years ago

Find the area of the shaded regions. Give your answer as a completely simplified exact value in terms of π (no approximations).

olga_2 [115]

Answer:

$7\pi cm^2$

Step-by-step explanation:

The area of a circle is given by $A=\pi r^2$

For circle B, the radius is 3 cm, it has an area of $\pi *3^2=9\pi cm^2$

Circle D also has a radius of 1 cm. Its area is $\pi *1^2=\pi cm^2$

Circle P also has a radius of 1 cm and area $\pi*1^2=\pi cm^2$

The area of the shaded region is then $9\pi -\pi-\pi=7\pi cm^2$

5 0

3 years ago

In a certain town, the wind speed, x, in km/h on a certain day is described by two statements: If 2 times the wind speed is incr

hodyreva [135]

<span>1) if 2 times the wind speed is increased by 2, the wind speed is still less than 46 km/h.

=> 2x + 2 < 46

2) Twice the wind speed minus 27 is greater than 11 km/h.

=> 2x - 27 > 11

Part A: Create a compound inequality to represent the wind speed range. (3 points)

from 2x + 2 < 46

=> 2x < 44

=> x < 22

from 2x - 27 > 11

=> 2x > 11 + 27

=> 2x > 38

=> x > 19

The set of inequalities is

2x + 2 <46
2x - 27 > 11

The solution is x < 22 and x > 19, which is:

19 < x < 22 <----- answer

Part B: Can the wind speed in this town be 20 km/h? Justify your answer by solving the inequalities in Part A. (3 points)

Yes, the wind speed can be 20 km/h, because the solution of the inequality is the range (19,22).

Part C: The average wind speed in another town is 23 km/h, but the actual wind speed is within 4 km/h of the average. Write and solve an inequality to find the range of wind speed in this town.

x ≥ 23 - 4 => x ≥ 19

x ≤ 23 + 4=> x ≤ 27

=> 19 ≤ x ≤ 27

=> [19,27]
</span>

4 0

3 years ago