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grin007 [14]
3 years ago
9

Describe the behavior of the graph at the x-intercepts for the functions f(x)=(2x-7)^7 (x+3)^4. Be sure to identify each x-inter

cept and justify your answer.

Mathematics
1 answer:
k0ka [10]3 years ago
3 0

Answer:

Touches at -3 and crosses at 3.5

Step-by-step explanation:

f(x)=(2x-7)^7 (x+3)^4 is given

To find x intercepts:

for x intercepts the value of f(x) =0

Hence f(x)=(2x-7)^7 (x+3)^4=0

Solving we get

2x-7 =0 or x+3 =0

x = 3.5 or x=-3

Thus we find the zeroes of the polynomial of f(x) are 3.5 and -3.

3.5 has a multiplicity of 7 and -3 a multiplicity of 4

Since 7 is odd, i.e. 3.5 has a multiplicity of odd number, hence f(x) crosses x axis at x 3.5

Since -3 has a multiplicity of an even number 4, we find that the curve touches x axis at the point -3.

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Answer:

R=883.74N

Step-by-step explanation:

From the question we are told that:

Force 1 F_1=226N

Force 2 F_2=331N

Force 3 F_3=377N

Direction 1  \theta_1=145 degrees \approx 35 \textdegree (2nd qudrant)

Direction 2 \theta_2=303 degrees \approx 57 \textdegree (3rd qudrant)

Direction 3 \theta_3=77 degrees

Generally Resolving forces to X axis is mathematically given by

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Generally Resolving forces to Y axis is mathematically given by

 \sum f_y=337sin77+331sin57+226cos35

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Generally the equation for Resultant force R is mathematically given by

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7 0
3 years ago
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garri49 [273]

Answer:

1. \frac{x^2}{y^8}

2 a) \frac{-49}{2}

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Step-by-step explanation:

1.

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2. a)

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3.

\frac{3}{4}x + \frac{5}{6} = 5x -\frac{125}{3} \\\frac{5}{6} + \frac{125}{3} = 5x - \frac{3}{4}x\\\frac{5+250}{6} = \frac{20x -3x}{4}\\\frac{255}{6} = \frac{17x}{4}\\x = 10

7 0
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<span>-6x-3y=18
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\boxed{(f\circ g)(x)=x^2}

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