Total number of ways to make a pair:
The first player can be any one of 7 . For each of those . . .
The opponent can be any one of the remaining 6 .
Total ways to make a pair = 7 x 6 = 42 ways .
BUT ... every pair can be made in two ways ... A vs B or B vs A .
So 42 'ways' make only (42/2) = 21 different pairs.
If every pair plays 2 matches, then (21 x 2) = <em><u>42 total matches</u></em> will be played.
Now, is that an elegant solution or what !
Answer:
13! or 6227020800
Step-by-step explanation:
With no restrictions, we can figure out the answer to be 13! by the following analysis:
For the first position in line, there are 13 different students who could fill that spot. If we fill it and proceed to the next position in line, there are now only 12 students left who can fill it, since one is already in line. Then the next position only has 11 possibilities, and the next 10, and so on.
Multiplying all of this together gives us 13*12*11*10*9*8*7*6*5*4*3*2*1 or 13!
Answer:
coefficient of x: 2
coefficient of y: 3
coefficient of z: -7
Step-by-step explanation:
To solve this problem, first we need to sum the polynomials A and B, then we need to check the coefficients of x, y and z.
The sum of the polynomials is:
A + B = 5z + 4x^2 - 6y + 2 + 2x + 9y - 12z - 2
A + B = 4x^2 + 2x + 3y - 7z
So, the coefficients are:
coefficient of x^2: 4
coefficient of x: 2
coefficient of y: 3
coefficient of z: -7
Answer:
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