Answer:
14
Step-by-step explanation:
Let n represent the number of nickels. Then the number of quarters is 36-n. The difference is ...
(36-n) -n = 8 . . . . . 8 more quarters than nickels
18 -n = 4 . . . . . . . divide by 2
14 = n . . . . . . . . add n-4 to both sides
There are 14 nickels in the jar.
_____
<em>Additional comment</em>
The problem supplies more information than is needed for a solution. You can work this as a "sum and difference" problem, as we have above, or you can work it as a "mixture" problem where the total coin value comes into play. Any two of the three given relations will give a solution.
n + q = 36 . . . . . . . number of coins
5n +25q = 620 . . . value of coins (in cents)
q -n = 8 . . . . . . . . difference in number of coins
Answer:
<h3>
14, 15, 16</h3>
Step-by-step explanation:
The consecutive integers iincrease by 1. So the middle integer of an odd number of consecutive integers is their mean. Three is an odd number of integers.
45:3 = 15 ← middle number
15 - 1 = 14 ← the smallest number
15 + 1 = 16 ← the largest number
For this problem, the confidence interval is the one we are looking
for. Since the confidence level is not given, we assume that it is 95%.
The formula for the confidence interval is: mean ± t (α/2)(n-1) * s √1 + 1/n
Where:
<span>
</span>
α= 5%
α/2
= 2.5%
t
0.025, 19 = 2.093 (check t table)
n
= 20
df
= n – 1 = 20 – 1 = 19
So plugging in our values:
8.41 ± 2.093 * 0.77 √ 1 + 1/20
= 8.41 ± 2.093 * 0.77 (1.0247)
= 8.41 ± 2.093 * 0.789019
= 8.41 ± 1.65141676
<span>= 6.7586 < x < 10.0614</span>
Answer:
1. 8/3
2. 1/7
3. 1/12
4. 1/27
Step-by-step explanation:
1. 3/8 * m = 1
Multiply by 8/3
8/3 * 3/8 m = 1* 8/3
m = 8/3
2. 7 * m = 1
Divide by 7
7*m /7 = 1/7
m = 1/7
3. 3 ÷m = 36
Multiply by m
3 ÷m * m = 36*m
3 = 36*m
Divide by 36
3/36 = 36*m/26
1/12 = m
4. 4/9 ÷m = 12
Multiply by m
4/9 ÷m * m = 12*m
4/9 = 12*m
Multiply by 1/12
4/9 *1/12 = 12*m * 1/12
4/12 *1/9 = m
1/3*1/9 =m
1/27
