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3 years ago

Helppp with those two I and j

Mathematics

1 answer:

andreev551 [17]3 years ago

3 0

Answer: For I the answer is m=55, for J the answer is x=24

Step-by-step explanation:

I. Remote interior angles add up to exterior which means 30+80=2m which is 110=2m. Divide 110 by 2 gives you m=55

J. Same concept but this time it is 5x=120, divide 120 by 5 gives you 24.

You might be interested in

What are the multiples of 18?

enot [183]

18,36,54,72,90,108,126,144,162,180,198,216,234,252,
hope this helps!

3 0

3 years ago

Read 2 more answers

Determine which function has the greatest rate of change as x approaches infinity.

Mekhanik [1.2K]

Answer: h(x) = 3*x^2 - 7*x + 8

Step-by-step explanation:

The rate of change of a function is equal to the derivate:

remember that a derivate of the form:

k(x) = a*x^n is k'(x) = n*a*x^(n-1)

Then we have:

f(x) = 2*x - 10

f'(x) = 1*2* = 2

g(x) = 16*x - 4

g'(x) = 1*16 = 16

h(x) = 3*x^2 - 7*x + 8

h'(x) = 2*3*x - 1*7 = 6*x - 7

So the only that increases as x increases is h(x), this means that the greates rate of change as x approaches inffinity is the rate of change of h(x)

3 0

3 years ago

How many terms of the arithmetic sequence {1,22,43,64,85,…} will give a sum of 2332? Show all steps including the formulas used

MA_775_DIABLO [31]

There's a slight problem with your question, but we'll get to that...

Consecutive terms of the sequence are separated by a fixed difference of 21 (22 = 1 + 21, 43 = 22 + 21, 64 = 43 + 21, and so on), so the n-th term of the sequence, a (n), is given recursively by

• a (1) = 1

• a (n) = a (n - 1) + 21 … … … for n > 1

We can find the explicit rule for the sequence by iterative substitution:

a (2) = a (1) + 21

a (3) = a (2) + 21 = (a (1) + 21) + 21 = a (1) + 2×21

a (4) = a (3) + 21 = (a (1) + 2×21) + 21 = a (1) + 3×21

and so on, with the general pattern

a (n) = a (1) + 21 (n - 1) = 21n - 20

Now, we're told that the sum of some number N of terms in this sequence is 2332. In other words, the N-th partial sum of the sequence is

a (1) + a (2) + a (3) + … + a (N - 1) + a (N) = 2332

or more compactly,

$\displaystyle\sum_{n=1}^N a(n) = 2332$

It's important to note that N must be some positive integer.

Replace a (n) by the explicit rule:

$\displaystyle\sum_{n=1}^N (21n-20) = 2332$

Expand the sum on the left as

$\displaystyle 21 \sum_{n=1}^N n-20\sum_{n=1}^N1 = 2332$

and recall the formulas,

$\displaystyle\sum_{k=1}^n1=\underbrace{1+1+\cdots+1}_{n\text{ times}}=n$

$\displaystyle\sum_{k=1}^nk=1+2+3+\cdots+n=\frac{n(n+1)}2$

So the sum of the first N terms of a (n) is such that

21 × N (N + 1)/2 - 20N = 2332

Solve for N :

21 (N ² + N) - 40N = 4664

21 N ² - 19 N - 4664 = 0

Now for the problem I mentioned at the start: this polynomial has no rational roots, and instead

N = (19 ± √392,137)/42 ≈ -14.45 or 15.36

so there is no positive integer N for which the first N terms of the sum add up to 2332.

4 0

2 years ago

Simplify i12. 1 −1 −i i

Likurg_2 [28]

Answer:

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Keenan will run 2.5 miles from his house to Jared’s house. He plans to hang out for 45 minutes before walking home. If he can ru

jenyasd209 [6]

Answer:

Kennan will be from home approximately an hour and 48 minutes.

Step-by-step explanation:

We must know that total time ( $t_{T}$ ) that Keenan will be from home is the sum of run ( $t_{R}$ ), hang out ( $t_{H}$ ) and walk times ( $t_{W}$ ), measured in hours: