Yes I did this and I would say yes, I got a 100%
Keq = products / reagents
N2O4(g) ⇄ 2 NO2(g)
Keq = [ NO2 ]² / [ N2O4 ]
hope this helps!
It has seven neutrons,
six protons,
Answer:
The straight carbon links indicate butane.
The hydrogen atoms are replaced by the methyl radical:
The first is 2-methylbutane.
The second is 2:2-dimethylbutane.
Answer:
2:1
1.2 × 10² g
Explanation:
Step 1: Write the balanced combustion equation
CH₄ + 2 O₂ ⇒ CO₂ + 2 H₂O
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of O₂ to CH₄ is 2:1.
Step 3: Calculate the moles of CH₄ required to react with 15 moles of O₂
We will use the previously established molar ratio.
15 mol O₂ 1 mol CH₄/2 mol O₂ = 7.5 mol CH₄
Step 4: Calculate the mass corresponding to 7.5 moles of CH₄
The molar mass of CH₄ is 16.04 g/mol.
7.5 mol × 16.04 g/mol = 1.2 × 10² g
