A sample of marble has a volume of 8 cm3 and a density of 2.75 g/cm3. What is its mass?

Chemistry

2 answers:

Firlakuza [10]3 years ago

7 0

Using the formula Density = Mass / Volume,

Mass = Density x Volume
Mass = 2.75 x 8 = 22g

Arte-miy333 [17]3 years ago

6 0

Answer: The correct answer is 22 g.

Explanation:

The expression for the relation between mass and density is as follows;

$Density=\frac{m}{V}$

Here, m is the mass of the object and V is the volume of the object.

It is given in the problem that A sample of marble has a volume of $8 cm^{3}$ and a density of $2.75 \frac{g}{cm^{3}}$ .

Calculate the mass of a sample marble.

$m= (Density)(V)$

Put $V=8 cm^{3}$ and $Density=2.75 \frac{g}{cm^{3}}$ .

$m= (2.75)(8)$

m=22 g

Therefore, the mass of a sample of a marble is 22 g.

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A solution is prepared by mixing 93.0 mL of 5.00 M HCl and 37.0 mL of 8.00 M HNO3. Water is then added until the final volume is

Charra [1.4K]

Answer:

$[H^{+}] = 0.761 \frac{mol}{L}$

$[OH^{-}]=1.33X10^{-14}\frac{mol}{L}$

$pH = 0.119$

Explanation:

HCl and HNO₃ both dissociate completely in water. A simple method is to determine the number of moles of proton from both these acids and dividing it by the total volume of solution.

$n_{H^{+} } from HCl = [HCl](\frac{mol}{L}). V_{HCl}(L) \\ n_{H^{+} } from HNO_{3} = [HNO_{3}](\frac{mol}{L}). V_{HNO_{3}}(L)$