1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
strojnjashka [21]
3 years ago
9

A sample of marble has a volume of 8 cm3 and a density of 2.75 g/cm3. What is its mass?

Chemistry
2 answers:
Firlakuza [10]3 years ago
7 0
Using the formula Density = Mass / Volume,

Mass = Density x Volume
Mass = 2.75 x 8 = 22g
Arte-miy333 [17]3 years ago
6 0

Answer: The correct answer is 22 g.

Explanation:

The expression for the relation between mass and density is as follows;

Density=\frac{m}{V}

Here, m is the mass of the object and V is the volume of the object.

It is given in the problem that A sample of marble has a volume of 8 cm^{3} and a density of  2.75 \frac{g}{cm^{3}}.

Calculate the mass of a sample marble.

m= (Density)(V)

Put V=8 cm^{3} and Density=2.75 \frac{g}{cm^{3}}.

m= (2.75)(8)

m=22 g

Therefore, the mass of a sample of a marble is 22 g.

You might be interested in
Which choice(s) correctly rank(s) the bonds in terms of increasing polarity?
Marina CMI [18]

Answer:

(II) only correctly rank the bonds in terms of increasing polarity.

Explanation:

Bond polarity is proportional to difference in electronegativity between bonded atoms.

Atoms    Electronegativity          Bond        Electronegativity difference

Cl                          3.0                       Cl-F                      1.0

Br                          2.8                       Br-Cl                     0.2

F                            4.0                       Cl-Cl                      0

H                            2.1                       H-C                       0.4

C                            2.5                       H-N                       0.9

N                             3.0                      H-O                       1.4

O                             3.5                      Br-F                       1.2

I                               2.7                      I-F                         1.3

Si                             1.9                      Cl-F                       1.0  

P                              2.2                      Si-Cl                      1.1

                                                          Si-P                        0.3

                                                          Si-C                        0.6

                                                           Si-F                        2.1

So, clearly, order of increasing polarity : O-H > N-H > C-H

So, (II) only correctly rank the bonds in terms of increasing polarity

4 0
3 years ago
Someone please help me with this ???
Verizon [17]

Answer:

c

Explanation:

6 0
2 years ago
How many moles of mercury(Hg) are in 1.30 *10.7 atoms or mercury
Svetach [21]
1 mole Hg --------------- 6.02x10²³ atoms
?? moles Hg ------------ 1.30x10⁷ atoms

(1.30x10⁷) x 1 / 6.02x10²³ => 2.159x10⁻¹⁷ moles 
5 0
3 years ago
Which solution has the highest boiling point at standard pressure?
julia-pushkina [17]
Pressure: when the external pressure is:
less than one atmosphere, the boiling point of the liquid is lower than its normal boiling point.
equal to one atmosphere, the boiling point of a liquid is called the normal boiling point.
greater than one atmosphere, the boiling point of the liquid is greater than its normal boiling point.
8 0
3 years ago
Read 2 more answers
At what temperature would 2.10moles of N2 gas have a pressure of 1.25atm and fill a 25.0 L tank
hodyreva [135]

Answer:

\large \boxed{\text{-92 $^{\circ}$C}}

Explanation:

We can use the Ideal Gas Law and solve for T.

pV = nRT

Data  

p = 1.25 atm

V = 25.0 L

n = 2.10 mol

R = 0.082 06 L·atm·K⁻¹mol⁻¹

Calculations

1. Temperature in kelvins

\begin{array} {rcl}pV & = & nRT\\\text{1.25 atm} \times \text{25.0 L} & = & \rm\text{2.10 mol} \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times T\\31.25&=&0.09847T\text{ K}^{-1}\\T& = &\dfrac{31.25}{\text{0.098 47 K}^{-1}}\\\\& = &\text{181 K}\end{array}

2. Temperature in degrees Celsius

\begin{array} {rcl}T & = & (181 - 273.15) \, ^{\circ}\text{C}\\& = & -92 \, ^{\circ}\text{C}\\\end{array}\\\text{The temperature of the gas is $\large \boxed{\mathbf{-92 \, ^{\circ}}\textbf{C}}$}

8 0
3 years ago
Other questions:
  • Deduce the structure of an unknown compound using the data below: Molecular Formula: C6H12O IR: 1705 cm-1 1H NMR: no absorptions
    8·1 answer
  • Guys i need help on this one
    12·1 answer
  • What changes could be made to optimize the manufacturing process
    15·1 answer
  • Please help me!!!!!!!!!!
    8·1 answer
  • Which element is the least metallic between cadmium, silver, zinc, or iron?
    7·1 answer
  • If 13.5 g NaCI were dissolved in 250.0 g of water, what is the mass percent of NaCI in the solution? What is the mass percent of
    10·1 answer
  • How many hydrogen atoms are found in 3H2CO3?
    11·1 answer
  • A gas is collected at 25.0 °C and 755.0 mm Hg. When the temperature is
    6·1 answer
  • ANSWER ASAP!!
    9·2 answers
  • The
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!