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2 years ago

Which statements best describe fossils? Check all that apply.

Chemistry

2 answers:

nikdorinn [45]2 years ago

3 0

Answer:

2&3&5

Explanation:

fossils are and can be all of the above

ololo11 [35]2 years ago

3 0

Answer:

2,3,5

Explanation:

i got it right

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It is considered a DUI if the driver’s Blood Alcohol Content level is at or above .08.

Tom [10]

I would put yes as in California the dui is .08 or above

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3 years ago

2NaHCO3-->Na2CO3+H2O+CO2

algol [13]

I’m not sure what kind of answer you’re looking for, but if you’re supposed to translate it into a sentence it would be two moles of sodium bicarbonate(baking soda) decompose unto one mole of sodium carbonate(soda ash) plus one mole of water and one mole of carbon monoxide gas

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2 years ago

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lisabon 2012 [21]

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3 years ago

Read 2 more answers

why is a molecule of CO2 non polar even though the bonds between the carbon atom and the oxygen atoms are polar

stira [4]

Answer:

Explanation:

5 0

2 years ago

GIVING BRAINLIEST One mole of hydrogen gas (H2), reacts with one mole of bromine Br2(g) to produce 2 moles of hydrogen bromide g

JulsSmile [24]

Answer:

The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

Explanation:

The standard enthalpy of formation or standard heat of formation of a compound is the change of enthalpy during the formation of 1 mole of the substance from its constituent elements, with all substances in their standard states.

Given, that 1 mole of $H_2$ gas and 1 mole of $Br_2$ liquid gives 2 moles of HBr gas as a product.The reaction releases 72.58 kJ of heat.

$H_2(g) + Br_2(l)\rightarrow 2HBr(g) ,\Delta H_{f}^o= -72.58kJ$

Divide the equation by 2.

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

The equation to show the the correct form to show the standard molar enthalpy of formation:

$\frac{1}{2}H_2(g) +\frac{1}{2}Br_2(l)\rightarrow HBr(g) ,\Delta H_{f}^o= -36.29 kJ$

4 0

3 years ago