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2 years ago

All of these are examples of an animal maintaining homeostasis EXCEPT:

Chemistry

1 answer:

Pie2 years ago

3 0

Answer:

A whale bleeding from a cut.

Explanation:

Shivering in the cold, breathing hard during exercise, and sweating because it's hot are ways the body is working to maintain good functioning and to keep the body alive. Bleeding from a cut is not an example of this.

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Question 10(Multiple Choice Worth 5 points)

jarptica [38.1K]

Answer:

O Generation of electricity

Explanation:

because the others dont make sense to me and tbh carbon is used everyway and everywhere

7 0

2 years ago

Sulfurous Acid, H2SO3, is a diprotic acid, with the following acid dissociation constants: Ka1 = 1.4 × 10-2 Ka2 = 6.7 × 10-8 Wha

Colt1911 [192]

Answer:

Kb = 7.1 x 10⁻¹³

Explanation:

Ka x Kb = Kw => Kb = 1 x 10⁻¹⁴/1.4 x 10⁻² = 7.1 x 10⁻¹³

3 0

3 years ago

Read 2 more answers

Carbon monoxide (CO) _____.

kirill [66]

Is a compound made of oxygen and carbon

7 0

2 years ago

Read 2 more answers

An industrial chemist is studying a sample of an

Natalija [7]

Answer:

the above

Explanation:

heat the metal until it melts

react it with o2

stretch it

react it with acid

5 0

3 years ago

Read 2 more answers

A solution is prepared by dissolving 42.0 g of glycerin, C3H8O3, in 186 g of water with a final volume of 200.0 mL. a. Calculate

trapecia [35]

Answer:

For a: The molality and molarity of the given solution is 2.45m and 2.28 M respectively.

For b: The molarity of the solution when more water is added is 0.912 M

Explanation:

For a:

To calculate the molality of solution, we use the equation:

$Molarity=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute $(C_3H_8O_3)$ = 42.0 g

$M_{solute}$ = Molar mass of solute $(C_3H_8O_3)$ = 92.093 g/mol

$W_{solvent}$ = Mass of solvent (water) = 186 g

Putting values in above equation, we get:

$\text{Molality of }C_3H_8O_3=\frac{42\times 1000}{92.093\times 186}\\\\\text{Molality of }C_3H_8O_3=2.45m$

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$ .....(1)

We are given:

Molarity of solution = ?

Molar mass of $(C_3H_8O_3)$ = 92.093 g/mol

Volume of solution = 200 mL

Mass of $(C_3H_8O_3)$ = 42 g

Putting values in above equation, we get:

$\text{Molality of }C_3H_8O_3=\frac{42\times 1000}{92.093\times 200}\\\\\text{Molality of }C_3H_8O_3=2.28M$

Hence, the molality and molarity of the given solution is 2.45m and 2.28 M respectively.

For b:

Now, the 300 mL water is added to the solution. So, the total volume of the solution becomes (200 + 300) = 500 mL

Using equation 1 to calculate the molarity of solution, we get:

Molar mass of $(C_3H_8O_3)$ = 92.093 g/mol

Volume of solution = 500 mL

Mass of $(C_3H_8O_3)$ = 42 g

Putting values in equation 1, we get:

$\text{Molality of }C_3H_8O_3=\frac{42\times 1000}{92.093\times 500}\\\\\text{Molality of }C_3H_8O_3=0.912M$

Hence, the molarity of the solution when more water is added is 0.912 M

5 0

3 years ago