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4 years ago

What does A equal? Plz help will mark BRAINLIEST ASAP!!!!

Mathematics

1 answer:

Ivanshal [37]4 years ago

5 0

Answer:

Step-by-step explanation:

((8+16)÷2)×4=48

so the area would be 48

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At the end of the ride up a steep hill, Ken was at an elevation of 1600 meters above where he started. He figured out that he an

Lostsunrise [7]

Answer:

Step-by-step explanation:

first place)

in first place you must Know by definition that a joule is defined as the amount of work done by a constant force in a meter of length

and it is 1 J = 1 N ×m = 1 kg ×m/s² ×m= 1 Kg×m²/s²

now you can calculate the time done by ken and his bicycle

1000000 = 52kg×(1600)²/s² = 1000000= 133120000/s²⇒1000000s² = 133120000⇒s²= 133120000/1000000⇒ s² =133,12⇒s =√133,12 = 11,5 ≅12

12 s is the time that ken with his bicycle ride up to the mountain

second )

having the time you can calculate the work done by ken individually

52kg×(1600)²/(12)² =133120000/ (12)² = 924444,4 and this is the work done by ken

Now you must substract the work done by ken and his bicycle from the work done by ken individually in order to know the work of the bicycle

1000000 joules -924444,4 joules = 75555,6 joules

Having this amount, you can calculate the mass of the bicycle

and it is 1 J = 1 N ×m = 1 kg ×m/s² ×m= 1 Kg×m²/s²

75555,6 = kg *(1600) ²/(12)²⇒ 75555,6 =17777,7kg⇒ Kg = 75555,6/17777,7 = 4,25 kg

the mass of the ken's bicycle is 4,25 kg

3 0

3 years ago

What is

disa [49]

<h3>Explanation:</h3>

There is a theorem :

$\mathbf{a^{2}-b^{2}=(a-b)(a+b)}$

Proof: open the brackets on right side of equality by using distributive property

RHS = a(a+b) - b(a+b)

RHS = $\mathrm{a^{2}+ab-ab-b^{2}}$

RHS = $\mathrm{a^{2}-b^{2}}$ = LHS

Using the above theorem you can solve every question you asked:

$\mathrm{4x^{2}-1=(2x)^{2}-1^{2}=(2x-1)(2x+1)}$
$\mathrm{9x^{2}-64=(3x)^{2}-(8)^{2}=(3x-8)(3x+8)}$

$\mathrm{49x^{2}-121=(7x)^{2}-(11)^{2}=(7x-11)(7x+11)}$

$\mathrm{4x^{2}-y^{2}=(2x)^{2}-y^{2}=(2x-y)(2x+y)}$

$\mathrm{9x^{2}-b^{2}=(3x)^{2}-b^{2}=(3x-b)(3x+b)}$

$\mathrm{16x^{2}-9b^{2}=(4x)^{2}-(3b)^{2}=(4x-3b)(4x+3b)}$

$\mathrm{x^{2}-42^{2}=(x-42)(x+42)}$

6 0

4 years ago

What is the area of the shaded portion of the circle? (16π – 32) in2 (16π – 8) in2 (64π – 32) in2 (64π – 8) in2

GrogVix [38]

Answer:

(16π - 32) in²

Step-by-step explanation:

In the picture attached, the circle is shown.

Area of one-quarter of circle = 1/4*Area of a circle = 1/4*π*radius² = 1/4*π*8² = 16π in²

Area of the triangle = 1/2*base*height = 1/2*8*8 = 32 in²

Shaded area = Area of one-quarter of circle - Area of the triangle = (16π - 32) in²

5 0

3 years ago

The mass of a bronze statue is 15,000 g. The density of bronze is about 8 g/cm^3. What is the volume of the bronze statue?

Annette [7]

Answer:1875cm^3

Step-by-step explanation:

Volume = mass/density

15,000/8=1875

8 0

4 years ago

Plssss answer <br><br> answer i will mark as brilliant <br> plsss

Marat540 [252]

Answer:

Step-by-step explanation:

30/5 =6 and yeah That's alll

5 0

3 years ago

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