Sq of 196 is 14 then x2 = 28 then 25= 5
The Pythagorean theorem computed shows that the length of the guy wire, to the nearest foot, is 207 ft.
<h3>How to solve the length?</h3>
Here, we have two similar right triangles, ΔABE and ΔCDE.
CD = 11 ft
DE = 2 ft
BD = 35 ft
First, find AB:
AB/11 = (35 + 2)/2
AB/11 = 37/2
Cross multiply
AB = (37 × 11)/2
AB = 203.5 ft
Then, apply Pythagorean Theorem to find AE:
AE = √(AB² + BE²)
AE = √(203.5² + 37²)
AE = 207 ft
Therefore, the length of the guy wire is 207 ft.
Learn more about Pythagorean theorem on:
brainly.com/question/654982
A x = 0
using the law of exponents 
= 1
for (6² )^ x = 1 then x = 0
B note that 
= 1 ⇒ x = 1
2 → 2^8 × 3^(-5) × 1^(-2) × 3^(-8) × 2^(-12) × 2^(28)
= 2^(8 -12 + 28) × 1 × 3^(- 5 - 8)
= 2^24 × 3^(- 13) = 2^(24)/3^(13) = 10.523 ( 3 dec. places)
Answer:
Peytons car travels 14.8 miles less than Madeline's car in with one gallon
Step-by-step explanation:
peytons car uses 1 gal to travel 22.1 miles and Madeline's care uses 1 gal to travel 36.9. 36.9-22.1 = 14.8
ta da
a. The difference between two outputs that are 1 unit apart.
You need to Use y2 - y1 / x2 - x1 to find the difference
I will choose x2 as 1 and x1 as 0
(29 - 21) / (1 - 0)
8/1 so The difference is 8 per 1 unit.
b. Use the same formula
I will choose -3 as x2 and -5 as x1
(5 - (-11)) / (-3 - (-5))
(5 + 11) / (-3 + 5)
16 / 2 so the difference is 16 per 2 units.
c. I will choose 2 as x2 and -1 as x1
(45 - 21) / (2 - (-1))
24/3 so the difference is 24 per 3 units.
d. The ratios of the differences to the input intervals reduced all equal each-other, which is 8 per 1 unit.
