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LUCKY_DIMON [66]
3 years ago
11

What is the mean of the data set 17,24,26,13

Mathematics
2 answers:
lyudmila [28]3 years ago
8 0
To find the mean you will have to add all the numbers. And then you will have to divide the sum on the amount of numbers there are.
So you will have to add 17, 24, 26, and 13 which will add up to 80. Now you will have to divide 80 by 4 because there are 4 different numbers so the answer would be 20.
Mrrafil [7]3 years ago
7 0

Answer:

20

Step-by-step explanation:

17+24+26+13=80 divided by how many numbers there are 80 divided by 4 = 20.

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PLS HELP MEEEI NEED ANSWERS ASAP ASAP
Brums [2.3K]

Answer:

Associative.

Step-by-step explanation:

In addition and multiplication, it does not matter which two numbers you put together first. On the left aide 6 is associated with 3. On the right side 3 is grouped with 7.  It doesn't matter where 3 goes. You still get the same answer.

(6 + 3) + 7 = 6 + (3 + 7)

   9    +  7   =  6  + 10

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6 0
3 years ago
Which expression is equivalent to...
olga_2 [115]

Answer:

8m^5

Step-by-step explanation:

Well we can simplify the numerator, by multiplying the 4 by the 6 and the m^3 and m^4 (add the exponents, explained in one of my previous answers I think)

This gives us the fraction: \frac{24m^7}{3m^2}

We can now divide the m^7 by m^2 by subtracting the exponents, and the reason why this works, is you're simply cancelling out the m's, If we express this in expanded form we have the following fraction: \frac{24 * m * m * m * m * m * m * m}{3 * m * m}

Since there is two m's in the denominator and there is also two (more than two) m's in the numerator, we can cancel those two m's out, and we get the fraction:

\frac{24 * m * m * m * m * m}{3} which can be simplified in exponent form as: \frac{24m^5}{3}, now all we have to do is divide the 24 by the 3, to get 8

This gives us the answer: 8m^5

6 0
1 year ago
I need help Please help.
asambeis [7]

Answer:

Step-by-step explanation:

Number of students 10

Problem 1. $625 for the bus hire per friday, So 625*4=$2500

Problem 2. 2500/25=$100 each for the whole 4 weeks

Problem 3.

10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each

20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each

30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each

41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each

Hope this is correct

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Answer:

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