Answer:
Associative.
Step-by-step explanation:
In addition and multiplication, it does not matter which two numbers you put together first. On the left aide 6 is associated with 3. On the right side 3 is grouped with 7. It doesn't matter where 3 goes. You still get the same answer.
(6 + 3) + 7 = 6 + (3 + 7)
9 + 7 = 6 + 10
16 = 16
Answer:

Step-by-step explanation:
Well we can simplify the numerator, by multiplying the 4 by the 6 and the m^3 and m^4 (add the exponents, explained in one of my previous answers I think)
This gives us the fraction: 
We can now divide the m^7 by m^2 by subtracting the exponents, and the reason why this works, is you're simply cancelling out the m's, If we express this in expanded form we have the following fraction: 
Since there is two m's in the denominator and there is also two (more than two) m's in the numerator, we can cancel those two m's out, and we get the fraction:
which can be simplified in exponent form as:
, now all we have to do is divide the 24 by the 3, to get 8
This gives us the answer: 
Answer:
Step-by-step explanation:
Number of students 10
Problem 1. $625 for the bus hire per friday, So 625*4=$2500
Problem 2. 2500/25=$100 each for the whole 4 weeks
Problem 3.
10 students tickets 220= 2200 for all tickets. The bus, 625/10 = $62.5*4= $250 dollars for the whole 4 weeks for the bus so in all each student pays $470 each
20 students, tickets 220=4400 for all tickets. The bus, 625/20=$31.25*4=$125 for the whole 4 weeks for the bus, so in all each student must pay $345 each
30 students, tickets 220 = 6600 for all tickets. The bus, 625/30 =$20.83*4=$83.32 for the whole 4 weeks for the bus, so in all each student must pay $303.32 each
41 students, tickets $160=$6560 for all tickets. The bus, because you need 2 buses at 625 each so $1250 for both buses 1250/41= 30.49*4=$121.96 for the whole 4 weeks for the bus. So in al each student must pay $281.96 each
Hope this is correct
<span>4000 so the answer is C
Hope this helps</span>
Answer:
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Step-by-step explanation:
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