3 years ago

What is the difference between a subset and a proper subset?

1 answer:

muminat3 years ago

6 0

Answer:

A subset is when all of the elements in the subset are in the actual set. A proper subset is a subset which the actual set has at least on more element than the proper subset.

Step-by-step explanation:

For example, Set A, {1,2,3} is a subset of B {1,2,3}. But Set C, {1,2} is a proper subset of B. Set {5,8} is a subset of {2,5,8}.

You might be interested in

The height of a triangle is 18 inches. Find the length of the base if the area of the triangle is 63 square inches

NNADVOKAT [17]

Answer:

7 inches

Step-by-step explanation:

The area of a triangle is found by

A = 1/2 bh

We know the height is 18 and the area is 63

63 = 1/2 (b)(18)

63 = 9b

Divide each side by 9

63/9 = 9b/9

7 = b

The base is 7 inches

7 0

3 years ago

Read 2 more answers

Use the graph below to answer the question that follows: graph of the curve that passes through the following points, 0, 3; pi o

kifflom [539]

2.5 is your best choice

4 0

3 years ago

Im so confused any help or sites would be awesome

denpristay [2]

If A = L x W. . . Then L = A/W

8 0

4 years ago

Read 2 more answers

Select all the equations that are true. Explain your thinking.

Flura [38]

Answer:

A,D,E,

Step-by-step explanation:

8 0

3 years ago

Find the area of the part of the circular paraboloid z = x2 + y2 where 0 x2 + y2 r2

amm1812

Parameterize the parabolic "cup" (call it $\mathcal S$ ) by

$\mathbf s(u,v)=\langle u\cos v,u\sin v,u^2\rangle$

with $0\le u\le r$ and $0\le v\le2\pi$ . Then the surface element is

$\mathrm dS=\|\mathbf s_u\times\mathbf s_v\|\,\mathrm du\,\mathrm dv=u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv$

and the area is given by the surface integral

$\displaystyle\iint_{\mathcal S}\mathrm dS=\int_{v=0}^{v=2\pi}\int_{u=0}^{u=r}u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv=\frac{\left((1+4r^2)^{3/2}-1\right)\pi}6$

5 0

4 years ago