Answer:
The most important resonance structure is 4 (attached picture). Its bon order is 
or 
.
Explanation:
A picture with 4 forms of the perchlorate structure is attached. The first structure has simple bonds. The second structure contains a double bond, the third structure has two double bonds and the fourth structure has three double bonds.
Formal charge = group number of the periodic table - number of bonds (number of bonding electrons / 2) - number of non-shared electrons (lone pairs)
The formal charges in the first structure is +3 in chlorine and -1 in oxygen.
The formal charges in the second structure is +2 in chlorine, -1 in oxygen and 0 in the double bond oxygen.
The formal charges in the third structure is +1 in chlorine, -1 in the single bond oxygens and 0 in the double bond oxygens.
The formal charges in the fourth structure is 0 in chlorine, -1 in the single bond oxygen and 0 in the double bond oxygens.
The most important resonance structure is given by:
- Most atoms have 0 formal charge.
- Lowest magnitude of formal charges.
- If there is a negative formal charge, it's on the most electronegative atom.
Hence, the fourth structure is the mosr important.
The bond order of the structure is:
Total number of bonds: 7
Total number of bond groups: 4
Bond order= 
The correct answer is Ozone.
Ozone, sometimes known as O3, is a poisonous and unstable gas. Ozone is a potent allotrope of oxygen; it absorbs heat when it is present in large quantities all over the earth. A molecule called ozone has three oxygen atoms in it. At ground level, it is dangerous and unstable. O3 O3's efficacy in treating infections, wounds, and several disorders has been extensively established. Before the turn of the century, it was employed to sterilize drinking water. One study found that ozone could cure 114 different ailments. Headaches, coughing, a dry throat, difficulty breathing, a heavy feeling in the chest, and fluid in the lungs can all be side effects of ozone exposure.
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The answer is A it depends on the distance
Answer:
250 kJ
Explanation:
Step 1: Given data
- Work performed by the system (w): 145 kJ (By convention, when the system performs work on the surroundings, w > 0)
- Heat absorbed by the system (q): 105 kJ (By convention, when the system absorbs heat from the surroundings, q > 0)
Step 2: Calculate the change in the internal energy of the system
The internal energy of a thermodynamic system is the energy contained within it. We can calculate the change in the internal energy (ΔE°) using the following expression.
ΔE° = q + w
ΔE° = 105 kJ + 145 kJ = 250 kJ
The options to the question above are:
A-the population of cladophora will decrease, resulting in an increase in the trout population
B-there will be a larger decrease in the trout population, resulting in an increase in damselfy nymphs
C- increased stream volume will provide more area for the trout to reproduce, causing a large increase in the population of algae
D- the population of trout will decrease because the population of damselfly nymphs will decline
The most likely immediate effect of an increase in runoff containing cadmium on the trophic structure of the river community is that there will be a larger decrease in the trout population, resulting in an increase in damselfy nymphs
- Cadmium is known to increase in the food chain and also pile up in humans. It is often taken up in water by algae, insects, and then up the food chain to fish, where it is piled up it in their gills, liver and kidneys .
It is a very toxic heavy metal that comes into the environment through anthropogenic sources such as poor quality of surface water, marine water.
Conclusively we can therefore say that Option b is the right answer because trout is negatively affected by but not the case with damselfly.
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