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3 years ago

10

A system performed 145 kJ of work on the surroundings and absorbed 105 kJ of heat from the surroundings. What is the change in e

nergy of the system?

1 answer:

grin007 [14]3 years ago

3 0

Answer:

250 kJ

Explanation:

Step 1: Given data

Work performed by the system (w): 145 kJ (By convention, when the system performs work on the surroundings, w > 0)

Heat absorbed by the system (q): 105 kJ (By convention, when the system absorbs heat from the surroundings, q > 0)

Step 2: Calculate the change in the internal energy of the system

The internal energy of a thermodynamic system is the energy contained within it. We can calculate the change in the internal energy (ΔE°) using the following expression.

ΔE° = q + w

ΔE° = 105 kJ + 145 kJ = 250 kJ

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$p_i=P\times \chi_1$

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