Answer is: a possible identity for the unknown compound is C₃H₈.
m(binary compound) = 10.0 g.
m(H₂O) = 16.3 g; mass of water.
M(O₂) = 32 g/mol; molar mass of oxygen.
M(binary compound) = 1.38 · 32 g/mol.
M(binary compound) = 44.16 g/mol.
n(binary compound) = 10 g ÷ 44.16 g/mol.
n(binary compound) = 0.225 mol; amount of substance.
n(H₂O) = 16.3 g ÷ 18 g/mol.
n(H₂O) = 0.9 mol; amount of water.
m(H₂O) : n(binary compound) = 0.9 mol ÷ 0.225 mol.
m(H₂O) : n(binary compound) = 4 : 1.
Unknown cpmpound has 4 times more hydrogen than water, it has 8 hydrogen atoms.
Second element in compound is carbon:
M(X) = 44.16 g/mol - 8 · 1.01 g/mol.
M(X) = 36.08 g/mol ÷ 3.
M(C) = 12.01 g/mol.
Answer:
185.05 g.
Explanation
Firstly, It is considered as a stichiometry problem.
From the balanced equation: 2LiCl → 2Li + Cl₂
It is clear that the stichiometry shows that 2.0 moles of LiCl is decomposed to give 2.0 moles of Li metal and 1.0 moles of Cl₂, which means that the molar ratio of LiCl : Li is (1.0 : 1.0) ratio.
We must convert the grams of Li metal (30.3 g) to moles (n = mass/atomic mass), atomic mass of Li = 6.941 g/mole.
n = (30.3 g) / (6.941 g/mole) = 4.365 moles.
Now, we can get the number of moles of LiCl that is needed to produce 4.365 moles of Li metal.
Using cross multiplication:
2.0 moles of LiCl → 2.0 moles of Li, from the stichiometry of the balanced equation.
??? moles of LiCl → 4.365 moles of Li.
The number of moles of LiCl that will produce 4.365 moles of Li (30.3 g) is (2.0 x 4.365 / 2.0) = 4.365 moles.
Finally, we should convert the number of moles of LiCl into grams (n = mass/molar mass).
Molar mass of LiCl = 42.394 g/mole.
mass = n x molar mass = (4.365 x 42.394) = 185.05 g.
Metals nonmetals and Metalloids is the answer
Answer:
3 NaOH (aq) + H3PO4 (aq) → Na3PO4 (aq) + 3 H2O (l)
Explanation:
This is an acid-base reaction (neutralization): NaOH is a base, H3PO4 is an acid.