Option b. 0.496
- Step-by-step explanation:
we know that
f(x)=0.01(2^{x})
The average rate of change is equal to
\frac{f(b)-f(a)}{b-a}
where
a=3
b=8
f(a)=f(3)=0.01(2^{3})=0.08
f(b)=f(8)=0.01(2^{8})=2.56
Substitute
\frac{2.56-0.08}{8-3}
\frac{2.48}{5}
0.496
We know that the sandbox is square, and that the area is 160 sq ft. Since A = s^2 for a square, let's work backwards and find s if A = 160 sq ft = s^2.
s^2 = 160 = 16(10). We do this because 16 is the largest perfect square factor of 160.
Then the length of one side of the square is approx. s = 4√10 ft (12.65 ft)
I am sorry I can help more but
Google can graph lines if that helps
You just look up graph of a line with your numbers
Answer:
-1 Degree C
Step-by-step explanation:
When its talking about average temperature, its talking about the mean. To calculate mean, you add all the numbers and divide it by how many numbers are there.
(-8) + (-1) + 2 + 4 + (-2) = -5
mean = -5/5
-1 degree C
Hi there!
a. Find the displacement by plugging in the values of the interval:
f(2) - f(0) = 0 - 2 = -2 meters.
Average velocity is the slope, thus:
The average velocity for the interval is -1 m/s.
b. To find the speed at the endpoints, we must take the derivative to get the velocity equation:
f(t) = t² - 3t +2
f'(t) = 2t - 3, at t = 0, speed = |-3| = 3 m/s. At t = 2, speed = 2(2) - 3 = 1 m/s.
Acceleration is the second derivative, thus:
f''(t) = 2. The acceleration is 2 m/s² for both endpoints.
c. When the body changes direction, the first derivative changes signs. Thus:
0 = 2t - 3
3 = 2t, t = 1.5 sec. This is where the body changes direction.
