The correct answer is phosphorylation. When an ADP (Adenine Diphosphate) molecule gains a phosphate, it becomes an (Adenine Triphosphate) molecule. This process is called a phosphorylation. Phosphorylation and its counterpart dephosphorylation change many proteins in terms of its functions and activities.
Answer:
They would not be able to achieve homeostasis.
Explanation:
Homeostasis refers to the maintenance of a stable internal environment and the cell needs a healthy and proper enzymes to do this.
Answer: choice B. Climate
Explanation:
Climate is the relative temperature of a region over time.
Answer:
In order to find average speed during each interval, we need to divide the distance during those intervals with the period of time. So, for the first interval (day 0 to day 2) hawksbill started from 0 and reached 10 kilometers by the end of the second day. That means that it crossed 10 kilometers in 2 days, so the average speed is 10/2 which is 5 km/day. Similarly, we can calculate speed for other intervals:
• day 2 - day 3: it went from 10 to 12 km in one day, which means it crossed 2 km in one day, so the average speed is 2/1 = 2 km/day
• day 3 - day 4: at the end of the third day it reached 12 km and at the end of the day 4 it remained at 12 km. That means the hawksbill wasn't moving in that interval so the speed was 0
• day 4 - day 5: it went from 12 km to 18 km, which means it crossed 18-12=6 km in one day, so the average speed is 6/1=6 km/day
• day 5 - day 6: it went from 18 to 24 km, which means it crossed 24-18=6 km in one day, so the speed was 6/1=6 km/day
So, to summarize, during the first interval turtle was moving with average speed of 5 km/day, then 2 km/day, in the third interval it wasn't moving and in the last two intervals, it moved in average speed of 6 km/day.
Answer:
The correct answer is option C. "disruptive selection".
Explanation:
Disruptive selection is a type of natural selection at which extreme values for a trait are favored, while intermediate traits are more likely to disappear. In this example the finches tended to have either small beaks or large beaks because small beaks are best at eating soft seeds and large beaks are best at cracking seeds. This is an example of disruptive selection because the two extreme values for the size of beaks are favored.
