The <span>hardy-weinberg equation is
p2 + 2pq + q2 = 1
where are already given with
c = 0.1 and C = 0.9
SO
p2 = 0.9^2
p2 = 0.81
q2 = 0.01
0.81 + 2pq - 0.01 = 1
2pq = 0.18
The answers are
CC = 0.81
cc = 0.01
Cc = 0.18</span><span />
Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
Answer:
Make reclamation mandatory after limestone has been removed
Explanation:
Answer:
D is answer
Explanation:
taiga is not an aquatic ecosystem
