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xz_007 [3.2K]
3 years ago
10

Which test is carried out 15 to 20 weeks into a pregnancy, and allows the analysis of fetal cells that can identify a variety of

genetic defects with nearly 100 percent accuracy?
Mathematics
1 answer:
BARSIC [14]3 years ago
6 0

Answer:

<u>Amniocentesis</u> is the test.

Step-by-step explanation:

Given:

Which test is carried out 15 to 20 weeks into a pregnancy, and allows the analysis of fetal cells that can identify a variety of genetic defects with nearly 100 percent accuracy?

Now, to find the test.

<u><em>Amniocentesis</em></u><em> is the test which is carried out 15 to 20 weeks into a pregnancy, and allows the analysis of fetal cells that can identify a variety of genetic defects with nearly 100 percent accuracy.</em>

<em>In this medical procedure some little amount of amniotic fluid is sampled through insertion of needle in the uterus which contain fetal tissues. Then the Fetal DNA is examined. This can also be used to determine sex of the foetus. This medical procedure is carried when women are between 15 to 20 weeks gestation.</em>

<em>In some countries there are some restrictions as this may use for sex determination</em> for example country like India.

Therefore, amniocentesis is the test.

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3 0
2 years ago
PLZ HELP OR I FAIL MY TEST
Volgvan

Answer:

time upstream=24/8=3 hours

time downstream=24/12=2 hours

Step-by-step explanation:

If R*T=D, and R is speed + or - current, how can you find the rate without the time, and how can you find the time without the rate?

THE KEY WAS WHEN WE WERE TOLD THAT IT TAKES ONE HOUR LONGER TO GO UPSTREAM THAN DOWNSTREAM BECAUSE T=D/R AND WE ARE TOLD THAT:

D/R(Upstream) minus 1 equals D/R (DOWNSTREAM)



Let x=rate of current

distance(d)=rate(r) times time(t) or d=rt or t=d/r

distance upstream=distance downstream=24 mi

rate upstream=10-x

rate downstream=10+x

time upstream=(distance upstream)/(rate upstream)=24/(10-x)

time downstream=(distance downstream)/(rate downstream)=24/(10+x)

Now, we are told that time upstream minus one hour equals time downstream. So our equation to solve is:

24/(10-x)-1=24/(10+x) Multiply both sides by (10-x)(10+x)

24(10+x)(10-x)/(10-x)-1(10-x)(10+x)=24(10-x)/(10+x)/(10+x) clear fractions


24(10+x)-(10-x)(10+x)=24(10-x) clear parens

240+24x-100-10x+10x+x^2=240-24x subtract 240 from and add 24x to both sides

240-240+24x+24x-100+x^2=240-240-24x+24x collect like terms

x^2+48x-100=0 ----------------quadratic equation in standard form

This equation can be factored:

(x+50)(x-2)=0

x=-50 mph----------------discount the negative value for speed

and

x=2 mph----------------------speed of the current

CK

10-x=10-2= 8 mph -----------------------speed upstream

10+x=10+2=12 mph--------------------------speed downstream

time upstream=24/8=3 hours

time downstream=24/12=2 hours

so 3-2=1----takes 1 hour longer upstream

7 0
2 years ago
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snow_lady [41]
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6 0
3 years ago
Ten coins weigh 25 grams how much does 1 coin weigh
kykrilka [37]
You need to divide here! Ok so if ten coins weigh twenty five grams, we need to do:
10÷25=?
Its easy if its ten you just shift the places. !0 divided by 25 is 2.5
8 0
3 years ago
QUESTION IN THE ATTACHMENT
eimsori [14]

Answer:

A. The sum of the first 10th term is 100.

B. The sum of the nth term is n²

Step-by-step explanation:

Data obtained from the question include:

Sum of 20th term (S20) = 400

Sum of 40th term (S40) = 1600

Sum of 10th term (S10) =..?

Sum of nth term (Sn) =..?

Recall:

Sn = n/2[2a + (n – 1)d]

Sn is the sum of the nth term.

n is the number of term.

a is the first term.

d is the common difference

We'll begin by calculating the first term and the common difference. This is illustrated below:

Sn = n/2 [2a + (n – 1)d]

S20 = 20/2 [2a + (20 – 1)d]

S20= 10 [2a + 19d]

S20 = 20a + 190d

But:

S20 = 400

400 = 20a + 190d .......(1)

S40 = 40/2 [2a + (40 – 1)d]

S40 = 20 [2a + 39d]

S40 = 40a + 780d

But

S40 = 1600

1600 = 40a + 780d....... (2)

400 = 20a + 190d .......(1)

1600 = 40a + 780d....... (2)

Solve by elimination method

Multiply equation 1 by 40 and multiply equation 2 by 20 as shown below:

40 x equation 1:

40 x (400 = 20a + 190d)

16000 = 800a + 7600. ........ (3)

20 x equation 2:

20 x (1600 = 40a + 780d)

32000 = 800a + 15600d......... (4)

Subtract equation 3 from equation 4

Equation 4 – Equation 3

32000 = 800a + 15600d

– 16000 = 800a + 7600d

16000 = 8000d

Divide both side by 8000

d = 16000/8000

d = 2

Substituting the value of d into equation 1

400 = 20a + 190d

d = 2

400 = 20a + (190 x 2)

400 = 20a + 380

Collect like terms

400 – 380 = 20a

20 = 20a

Divide both side by 20

a = 20/20

a = 1

Therefore,

First term (a) = 1.

Common difference (d) = 2.

A. Determination of the sum of the 10th term.

First term (a) = 1.

Common difference (d) = 2

Number of term (n) = 10

Sum of 10th term (S10) =..?

Sn = n/2 [2a + (n – 1)d]

S10 = 10/2 [2x1 + (10 – 1)2]

S10 = 5 [2 + 9x2]

S10 = 5 [2 + 18]

S10 = 5 x 20

S10 = 100

Therefore, the sum of the first 10th term is 100.

B. Determination of the sum of the nth term.

First term (a) = 1.

Common difference (d) = 2

Sum of nth term (Sn) =..?

Sn = n/2 [2a + (n – 1)d]

Sn = n/2 [2x1 + (n – 1)2]

Sn = n/2 [2 + 2n – 2]

Sn = n/2 [2 – 2 + 2n ]

Sn = n/2 [ 2n ]

Sn = n²

Therefore, the sum of the nth term is n²

6 0
2 years ago
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