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xz_007 [3.2K]
3 years ago
10

Which test is carried out 15 to 20 weeks into a pregnancy, and allows the analysis of fetal cells that can identify a variety of

genetic defects with nearly 100 percent accuracy?
Mathematics
1 answer:
BARSIC [14]3 years ago
6 0

Answer:

<u>Amniocentesis</u> is the test.

Step-by-step explanation:

Given:

Which test is carried out 15 to 20 weeks into a pregnancy, and allows the analysis of fetal cells that can identify a variety of genetic defects with nearly 100 percent accuracy?

Now, to find the test.

<u><em>Amniocentesis</em></u><em> is the test which is carried out 15 to 20 weeks into a pregnancy, and allows the analysis of fetal cells that can identify a variety of genetic defects with nearly 100 percent accuracy.</em>

<em>In this medical procedure some little amount of amniotic fluid is sampled through insertion of needle in the uterus which contain fetal tissues. Then the Fetal DNA is examined. This can also be used to determine sex of the foetus. This medical procedure is carried when women are between 15 to 20 weeks gestation.</em>

<em>In some countries there are some restrictions as this may use for sex determination</em> for example country like India.

Therefore, amniocentesis is the test.

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How do you solve the equation F = 9/5(K - 273.15) + 32 when you're solving for K?
Mumz [18]

\displaystyle\\Answer:\ K=\frac{5}{9}(F-32^0)+273.15^0

Step-by-step explanation:

\displaystyle\\F=\frac{9}{5} (K-273.15)+32\\F-32=\frac{9}{5} (K-273.15)+32-32\\F-32=\frac{9}{5} (k-273.15)\\Multiply\  both\  parts\  of\  the\  equation\  by\ \frac{5}{9} \\(\frac{5}{9})(F-32)=\frac{9}{5}  (K-273.15)(\frac{5}{9} )\\\\\frac{5}{9} (F-32)=K-273.15\\\\\frac{5}{9} (F-32)+273.15=K-273.15+273.15\\\\\frac{5}{9} (F-32)+273.15=K

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A changes saved<br> Set up a proportion and use it to solve for x.<br> 2<br> 10<br> х<br> 3
V125BC [204]

Answer:

C. 15

Step-by-step explanation:

The following proportional can be set-up for the figure given:

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Solve for x

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15 = x

x = 15

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3 years ago
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