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Strike441 [17]
3 years ago
12

Figure ABCD is a rhombus where the m∠ABC = 84 and m∠ABE = 3x − 6. Solve for x. Rhombus ABCD with diagonals AC and BD and point E

as the point of intersection of the diagonals. 16 30 32 62

Mathematics
2 answers:
sladkih [1.3K]3 years ago
5 0

Answer:

16

Step-by-step explanation:

bazaltina [42]3 years ago
4 0

Answer:

<u> x = 16</u>

Step-by-step explanation:

See the attched figure

We should know that, one of the properties of the rhombus is the diagonals bisect the angles of the rhombus.

Given:

m∠ABC = 84  and m∠ABE = 3x − 6

So, m∠ABE = 0.5 * m∠ABC = 0.5 * 84 = 42

∴ 3x - 6 = 42

Solve for x

3x = 42 + 6 = 48

x = 48/3 = 16

<u>∴ x = 16</u>

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