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jeka94
3 years ago
13

20 POINTS! Please help, best answer will recessive brainliest answer points as well as 5 stars and a thank you. :)

Mathematics
1 answer:
Kaylis [27]3 years ago
8 0

Answer:

13

Step-by-step explanation:

Diagonals of a rhombus are perpendicular bisector.

Hence, triangle ABE so formed would be a right triangle right angled at E.

Therefore, by Pythagoras theorem:

AB =  \sqrt{AE^2 + BE^2 }  \\  \\  \therefore \: AB =  \sqrt{5^2 + 12^2 }  \\  \\  =  \sqrt{25 + 144}  \\  \\  =  \sqrt{169}  \\  \huge \red { \boxed{ \therefore \: AB= 13}}

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3 years ago
3 ones - 22 tenths equal
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What is ∑n=15[5(−2)n−1] equal to?
kicyunya [14]

Answer:

Although the notation is sloppy, I will assume based on former questions of the same that "∑n=15[5(−2)^n−1]" translates mathematically to . Please correct me, though, if this in incorrect.

Anyway, there is neat formula that will deal with question very quickly. It is the following:

Sn is the sum of the geometric series

a1 is the first term in the series

r is the common ratio

n is the number of terms in the finite geometric series

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2 years ago
Use the percent formula, A = PB, where A is P percent of B, to answer the following question. What is 24% of 60?
Paladinen [302]

It should be noted that 24 percent of 60 is 14.4.

<h3>How to calculate the percentage?</h3>

The question is to calculate 24% of 60.

This will go thus:

= 24% × 60

= 24/100 × 60

= 0.24 × 60

= 14.4

Therefore, 24% of 60 is 14.4.

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brainly.com/question/24877689

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6 0
2 years ago
WILL GIVE BRAINLIEST
stira [4]

The air force plane travelled for a total of 6.9 hours.

<u>SOLUTION: </u>

Given, An Air Force plane left Nairobi and flew west at an average speed of 159 mph.  A cargo plane left sometime later flying in the same direction at an average speed of 207 mph.  After flying for 5.3 hours the cargo plane caught up with the Air Force plane.  

We have to find the number of hours the Air Force plane flew before the cargo plane caught up.

Now, we know that, \text { distance travelled }=\text { speed } \times \text { time }

For air force plane \rightarrow \text { distance travelled }=159 \mathrm{x} \text { time taken by air force plane }

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Now, when cargo plane caught the air force plane the distance travelled by the planes will be equal.

So, 159 \times \text { time taken by air force plane }=207 \times 5.3

\Rightarrow =\frac{207 \times 5.3}{159}

\Rightarrow =\frac{1097.1}{159}

Time taken by air force plane = 6.9  hrs

6 0
3 years ago
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