Answer:
22w - 18
Step-by-step explanation:
To find the perimeter we have to add up all the sides
10w-10+w+1+10w-10+w+1
combine light terms
22w - 18 would be our answer
Brainliest please
Answer:
Step-by-step explanation:
i Believe its A. B. And D. But i could be wrong
Answer:
The possible y-coordinate of point C is 6
Step-by-step explanation:
The coordinate of a point is given by (x,y) where x is the horizontal distance from the origin on the x axis and y is the vertical distance from the origin.
Given Segment AB is on the line y = 2 and is 3 units long and Segment AB is on the line y = 2 and is 3 units long. The area of triangle ABC is 6 square units.
The area of a triangle = 1/2 × base × height
6 = 1/2 × 3 × height
height = (2 × 6) / 3 = 4 units
Since point C is perpendicular to line y = 2, they coordinates is either 2 + 4 = 6 or 2 - 4 = -2
The coordinate of point C is either (-1, 6) or (-1, -2)
Answer:
The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
Suppose a sample of 1537 tenth graders is drawn. Of the students sampled, 1184 read above the eighth grade level. So 1537 - 1184 = 353 read at or below this level. Then
95% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval for the population proportion of tenth graders reading at or below the eighth grade level is (0.2087, 0.2507).
Answer:
The number of bacteria 
after 
days is given by
where 
is the initial number of bacteria.
Step-by-step explanation:
The number of bacteria in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is
where is the initial number of bacteria in the sample.
After the 2nd 10th days, the number of bacteria is
after the 3rd day,
and so on.
Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is
where 
is is the <em>n</em>th 10-days.
Since, is 10 days, we have
or
Substituting that into , we get:
