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IrinaVladis [17]
3 years ago
9

Whats 9+10???? i really need to know this

Mathematics
2 answers:
madreJ [45]3 years ago
8 0

Answer:

19

Step-by-step explanation:

marysya [2.9K]3 years ago
8 0

Answer:

are you asking 9 <em>plus </em>10? thats 19

Step-by-step explanation:

i have no idea what you are asking, but if you add 9 to 10 or 10 to 9, you get 19...1 less than 20

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Find the slope of a line with equation 4y + x = 8.
uranmaximum [27]

Answer:

m = -1/4

Step-by-step explanation:

4y + x = 8

Arrange the equation in a slope intercept form y = mx+b, where m is the slope

4y + x = 8, subtract x from both sides

    4y = -x +8, divide both sides by 4

      y = -x/4 + 8/4 , simplify

      y = -x/4 + 2, compare this to the general form y=mx+b and we see that the slope m = -1/4

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2 years ago
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The altitude of a plane is 1,600 ft. What must be the altitude of a submarine so that the sum of their altitudes is 0?
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You must mean the depth of the submarine.

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3 years ago
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1) Twice a number decreased by four is 32.<br> What is the number?
jeyben [28]

Answer:

6

Step-by-step explanation:

7 0
3 years ago
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HELP ON A TEST
sergejj [24]

Answer:

(-1, 6)

Step-by-step explanation:

The midpoint of a line segment is effectively the point that lies halfway between two pairs of coordinates on a line. The coordinates we're concerned with here are (-4, 10) and (2, 2). So first think about what is halfway between -4 and 2 (or you can add -4 and 2 then divide by 2) and do the same with 10 and 2. This will give you (-1, 6).

5 0
2 years ago
A quality analyst of a tennis racquet manufacturing plant investigates if the length of a junior's tennis racquet conforms to th
Burka [1]

Answer:

Confidence interval : 21.506 to 24.493

Step-by-step explanation:

A quality analyst selects twenty racquets and obtains the following lengths:

21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

So, sample size = n =20

Now we are supposed to find Construct a 99.9% confidence interval for the mean length of all the junior's tennis racquets manufactured at this plant.

Since n < 30

So we will use t-distribution

Confidence level = 99.9%

Significance level = α = 0.001

Now calculate the sample mean

X=21, 25, 23, 22, 24, 21, 25, 21, 23, 26, 21, 24, 22, 24, 23, 21, 21, 26, 23, 24

Sample mean = \bar{x}=\frac{\sum x}{n}

Sample mean = \bar{x}=\frac{21+25+23+22+24+21+25+21+23+ 26+ 21+24+22+ 24+23+21+ 21+ 26+23+ 24}{20}

Sample mean = \bar{x}=23

Sample standard deviation = \sqrt{\frac{\sum(x-\bar{x})^2}{n-1}}

Sample standard deviation = \sqrt{\frac{(21-23)^2+(25-23)^2+(23-23)^2+(22-23)^2+(24-23)^2+(21-23)^2+(25-23)^2+(21-23)^2+(23-23)^2+(26-23)^2+(21-23)^2+(24-23)^2+(22-23)^2+(24-23)^2+(23-23)^2+(21-23)^2+(21-23)^2+(26-23)^2+(23-23)^2+(24-23)^2}{20-1}}

Sample standard deviation= s = 1.72

Degree of freedom = n-1 = 20-1 -19

Critical value of t using the t-distribution table t_{\frac{\alpha}{2} = 3.883

Formula of confidence interval : \bar{x} \pm t_{\frac{\alpha}{2}} \times \frac{s}{\sqrt{n}}

Substitute the values in the formula

Confidence interval : 23 \pm 1.73 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 23 -3.883 \times \frac{1.72}{\sqrt{20}} to 23 + 3.883 \times \frac{1.72}{\sqrt{20}}

Confidence interval : 21.506 to 24.493

Hence Confidence interval : 21.506 to 24.493

3 0
3 years ago
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