Answer:
(a)
(b)
(c)
(d)
(e)
(f)
Step-by-step explanation:
Let as consider the given equations are
.
(a)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(b)
![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(c)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(d)

![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(e)


![[\because \log_aa^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog_aa%5Ex%3Dx%5D)
(f)


![[\because \log10^x=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Clog10%5Ex%3Dx%5D)
Answer:
x = 11/9
Step-by-step explanation:
Eliminate parentheses, add 16x, subtract 21.
7(3 -x) = 8(4 -2x) . . . . given
21 -7x = 32 -16x . . . . . eliminate parentheses using the distributive property
9x +21 = 32 . . . . . . . . add 16x
9x = 11 . . . . . . . . . . . . subtract 21
x = 11/9 . . . . . . . . . . . .divide by the coefficient of x
There are, 20475 different groups are possible if the manager wants to select one group of 4 people from his 28 assistants.
<h3>What is permutation and combination?</h3>
A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.
We have:
A manager wants to select one group of 4 people from his 28 assistants.
The total number of groups possible = C(28, 4)

After calculating:
= 20475
Thus, there are, 20475 different groups are possible if the manager wants to select one group of 4 people from his 28 assistants.
Learn more about permutation and combination here:
brainly.com/question/2295036
#SPJ1
<u>First let's calculate the exponents.</u>

<u>Now we should multiply and divide.</u>
<u />
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<u>Now we should add and subtract.</u>
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<u />
<u>Convert the improper fractions into mixed numbers.</u>
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<u />
<u />
<u>Answer : </u>
<u />
<u />
<u />
Greetings!To find the length of any side of a
right triangle, you can use the
Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
Input the information from the diagram into the formula:
Expand each term:



Combine like terms:
Add -169 to both sides:

Factor out the Common Term (2):
Factor the Complex Trinomial:



Set Factors to equal
0:


or


However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)
The Solution Is:

I hope this helped!
-Benjamin