The answer is C.<span>consistent and independent</span>
1) Graph the corresponding equation \( x = 2 \); this will split the plane into two regions. One of the region represents the solution set.
2) Select a point situated in any of the two regions obtained and test the inequality. If the point selected is a solution, then all the region is the solution set. If the selected point is not a solution, then the other (second) region represents the solution set.
3) Test: In this example, let us for example select the point with coordinates (3 , 2) which is in the region to the right of the line x = 2. If you substitute x in the inequality \( x ≥ 2 \) by 3 it becomes \( 3 ≥ 2 \) which is a true statement and therefore (3 , 2) is a solution. Hence, we can conclude that the region to the right of the vertical line x = 2 is a solution set including the line itself which is shown as a solid line because of the inequality symbol \( ≥ \) contains the \( = \) symbol. The solution set is represented by the blue hash region in the graph below including the line x = 2.
f(x)= -2x+1 {-2,0,2,4,6}
If x=-2, then -2(-2)+1 = 5
If x=0, then -2(0)+1 = 1
If x=2, then -2(2)+1 = -3
If x=4, then -2(4)+1 = -7
If x=6, then -2(6)+1 = -11
Answer:
B {5,1,-3,-7,-11}
