Molarity is defined as the number of moles of solute in volume of 1 L solution.
the molarity of KOH solution to be prepared is 0.500 M
the volume of solution to be prepared is 250 mL
the number of KOH moles in 1 L - 0.500 mol
therefore number of KOH moles in 250 mL - 0.500 mol/L x 0.250 L = 0.125 mol
Mass of KOH in 0.125 mol - 0.125 mol x 56.10 g/mol = 7.01 g
The mass of KOH required to make the solution is therefore 7.01 g
Depending on the type of waves you can say both matter and energy
Partial pressure of gas A is 1.31 atm and that of gas B is 0.44 atm.
The partial pressure of a gas in a mixture can be calculated as
Pi = Xi x P
Where Pi is the partial pressure; Xi is mole fraction and P is the total pressure of the mixture.
Therefore we have Pa = Xa x P and Pb = Xb x P
Let us find Xa and Xb
Χa = mol a/ total moles = 2.50/(2.50+0.85) = 2.50/3.35 = 0.746
Xb = mol b/total moles = 0.85/(2.50+0.85) = 0.85/3.35 = 0.254
Total pressure P is given as 1.75 atm
Pa = Xa x P = 0.746 x 1.75 = 1.31atm
Partial pressure of gas A is 1.31 atm
Pb = Xb x P = 0.254 x 1.75 = 0.44atm
Partial pressure of gas B is 0.44 atm.
Learn more about Partial pressure here:
brainly.com/question/15302032
#SPJ4