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olya-2409 [2.1K]
2 years ago
7

Based on the six given solvents, which of the following answers lists ALL of the solvents that are NOT suitable for liquid-liqui

d extraction of an aqueous layer?
1. Ethyl Acetate
2. Acetone
3. Methanol
4. Dimethyl Sulfoxide
5. Toluene
6. n-Octanol
A. Ethyl Acetate, Toluene, and n-Octanol
B. Dimethyl sulfoxide, Acetone, and Methanol
C. Toluene and n-Octanol
D. Ethyl Acetate and Dimethyl Sulfoxide
E. Acetone and n-Octanol
A. Ethyl Acetate, Toluene, and n-Octanol
B. Dimethyl sulfoxide, Acetone, and Methanol
C. Toluene and n-Octanol
D. Ethyl Acetate and Dimethyl Sulfoxide
E. Acetone and n-Octanol
Chemistry
1 answer:
Zina [86]2 years ago
6 0

Answer:

I don't know the answer sorry

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In the periodic table how many elements could be classified as metals in group IV?
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How many moles of oxygen (O2) are present in 33.6 L of the gas at 1 atm and 0°C?
maw [93]

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Explanation:

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If 500.0 mL of 0.450 M sodium phosphate is reacted with an excess of iron (II) nitrate solution, how many grams of iron (II) pho
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If 500.0 mL of 0.450 M sodium phosphate is reacted with an excess of iron (II) nitrate solution, how many grams of iron (II) phosphate are produced?

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Explanation:

8 0
3 years ago
An ideal gas at a given initial state expands to a fixed final volume. would the work be greater if the expansion occurs at cons
crimeas [40]

Answer:

Constant pressure

Explanation:

At constant pressure,

w = -p\Delta V = -p(V_{f} - V_{i})

At constant temperature,

w = -RT \ln \left(\dfrac{V_{f}}{V_{i}} \right)

1 mol of an ideal gas at STP has a volume of 22.71 L.

Let's compare the work done as it expands under each condition from an initial volume of 22.71 L.

Isobaric expansion

w = -100p(V_{2} - 22.71}); \text{(1 bar$\cdot$L = 100 J)}

A plot of -w vs V₂ gives a straight line (red) with a constant slope of 100 J/L as in the diagram below (Note that w is work done on the system, so -w is the work done by the system). \

Isothermal expansion

w= -8.314 \times 273.15 \ln \left(\dfrac{V_{f}}{22.71} \right)\\\\= -2271 \left( \ln V_{f} -\ln22.71 \right)\\= -2271 \left(\ln V_{f} - 3.123 \right)\\= 7092 - 2271\ln V_{f}

A plot of -w vs V₂ is a logarithmic curve. Its slope starts at 100 J/mol but decreases as the volume increases (the blue curve below).

Thus, the work done during an expansion at constant pressure is greater than if the system is at constant temperature.

4 0
3 years ago
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