Question

A beaker contains 42.0 mL of carbon tetrachloride ( CCl4 , density is 1.59 g/mL). Determine how many molecules of carbon tetrachloride are in the beaker.

Answer 1

Answer:

Number of molecules = 2.61  x 10²³

Explanation:

Given:

Volume of tetra-chloride = 42 ml

Density = 1.59 g/ml

Find:

Number of molecules

Computation:

Mass = Volume of tetra-chloride x Density

Mass = 42 x 1.59

Mass = 66.78

Molecular mass of tetra-chloride = 154 g/mol

Moles = 66.78 / 154

Moles = 0.4337

0.4337 mole = 0.4337 x Avogadro number

0.4337 mole = 0.4337 x 6.022 x 10²³

Number of molecules = 2.61  x 10²³