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givi [52]
3 years ago
14

A coin flipped 14 times and it comes up heads 10 times what is the experimental probability of the coin’s coming up heads ?

Mathematics
2 answers:
Alexus [3.1K]3 years ago
5 0

Answer:

(B) \dfrac{5}{7}

Step-by-step explanation:

If the coin is flipped 14 times

The Total Number of Trial in the Experiment =14

It comes up heads 10 times

This Means: Number of Successful Outcome of HEADS =10

In an <u>experimental probability</u>,

Experimental probability of the coin’s coming up heads

=Number of Successful Outcome of HEADS/Total Number of Trials in the Experiment

=\dfrac{10}{14}=\dfrac{5}{7}

Gekata [30.6K]3 years ago
3 0

The answer is B.

If a coin is flipped 14 times and lands on heads 10 times the fraction would equal to 10/14.

10/14 simplifies to 5/7.

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Step-by-step explanation:

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3 years ago
Find the midpoint of the line segment with the endpoints A and B.
zavuch27 [327]

Answer:

<h2>( 6 , 7 )</h2>

Step-by-step explanation:

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M = (  \frac{x1 + x2}{2} , \:  \frac{y1 + y2}{2} )\\

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m = ( \frac{2 + 10}{2} \:  , \:  \frac{6 + 8}{2} ) \\  =  (\frac{12}{2}  \: , \:  \frac{14}{2} ) \:  \:  \:  \:  \:  \:  \:

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3 0
3 years ago
Find the value of the variable.
nalin [4]

Answer:

The variable, y is 11°

Step-by-step explanation:

The given parameters are;

in triangle ΔABC;          {}              in triangle ΔFGH;

Segment \overline {AB} = 14         {}               Segment \overline {FG} = 14

Segment \overline {BC} = 27         {}              Segment \overline {GH} = 19

Segment \overline {AC} = 19         {}               Segment \overline {FH} = 2·y + 5

∡A = 32°                       {}                ∡G = 32°

∡A = ∠BAC which is the angle formed by segments \overline {AB} = 14 and \overline {AC} = 19

Therefore, segment \overline {BC} = 27, is the segment opposite to ∡A = 32°

Similarly, ∡G = ∠FGH which is the angle formed by segments \overline {FG} = 14 and \overline {GH} = 19

Therefore, segment \overline {FH} = 2·y + 5, is the segment opposite to ∡A = 32° and triangle ΔABC ≅ ΔFGH by Side-Angle-Side congruency rule which gives;

\overline {FH} ≅ \overline {BC} by Congruent Parts of Congruent Triangles are Congruent (CPCTC)

∴ \overline {FH} = \overline {BC} = 27° y definition of congruency

\overline {FH} = 2·y + 5 = 27° by transitive property

∴ 2·y + 5 = 27°

2·y = 27° - 5° = 22°

y = 22°/2 = 11°

The variable, y = 11°

8 0
3 years ago
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